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sergij07 [2.7K]

4 years ago

14

At the recycling center, 394 cansare to be organized into 10 green bins, and 560 bottles are to be organized into 12 blue bins.

Use estimation to decide which type bin has more items. About how many items are in this bin?

1 answer:

WINSTONCH [101]4 years ago

6 0

393 divided by 10 and then 560 divided by 12

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According to Greg, perfect cherry pies have a ratio of 240 cherries to 3 pies. How many cherries does Greg need to make 9 perfec

vfiekz [6]

Simple, 3 goes in to 9, 3 times. That would mean that to find the number of cherries, multiply 240 by 3. Greg needs 720 cherries for 9 perfect cherry pies.

6 0

4 years ago

Read 2 more answers

Graph f(x)=3x-1 and g(x)=2^x on the same coordinate plane.

julsineya [31]

Answer:

B. 1 and D. 3.

Step-by-step explanation:

The figure below shows the graphs of f(x) = 3x - 1 (red) and g(x) = 2^x (blue).

The solutions of 3x - 1 = 2^x are the points at which the two curves intersect.

The solutions are at x = 1 and x = 3.

Check:

3 × 1 - 1 = 2¹ 3 × 3 -1 = 2³

3 - 1 = 2 9 - 1 = 8

2 = 2 8 = 8

7 0

4 years ago

For this entry, you are a math expert at a local school. Explain to a group of students how independent and dependent events are

GaryK [48]

Answer:

hope this helps!

Step-by-step explanation:

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3 0

4 years ago

Austin walks 1/3 of the way to school and stopped to rest. Devyn walks 2/6 of the way to the school and stops to rest who travel

r-ruslan [8.4K]

Answer:

Austin and Devyn.

Step-by-step explanation:

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7 0

3 years ago

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is <em>N</em> (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

(c) The value of $P(\bar X\geq 69.1)$ is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$

And the standard deviation of the distribution of the sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74$

Thus, the distribution of the sample mean ( $\bar x$ ) is <em>N</em> (68, 4.74²).

(b)

Compute the value of $P(\bar X$ as follows:

$P(\bar X$

$=P(Z$

*Use a <em>z</em>-table for the probability.

Thus, the value of $P(\bar X$ is 0.7642.

(c)

Compute the value of $P(\bar X\geq 69.1)$ as follows:

Apply continuity correction as follows:

$P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)$

$=P(\bar X>69.6)$

$=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})$

$=P(Z>0.34)\\=1-P(Z$

Thus, the value of $P(\bar X\geq 69.1)$ is 0.3670.

7 0

4 years ago