5 + 2z/3 + 1 what is this? please help
1 answer:
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The values that correctly models the scenario of the rollercoaster graph will be:
- Red (x) = 6 + 4 × cos(πx/6) if 0 ≤ x < 6
- Green (x) = -2.5 × cos(π(x - 6)/4) + 4.5
- Purple (x) = 3.5 - 3.5 × sin(π(x - 12.5)/5)
From the complete question,
For Red (x) = 6 + 4 × cos(πx/6) if 0 ≤ x < 6
where at x = 0, Red(x) = 10,
at x = 5, Red(x) = 2.5
For Green (x) = -2.5 × cos(π(x - 6)/4) + 4.5 if 6 ≤ x < 10
where at x = 10, Green (x) = 7,
at x = 6, Green (x) = 2.0
For Purple (x) = 3.5 - 3.5 × sin(π(x - 12.5)/5) if 10 ≤ x ≤ 15
where at x = 10, Purple (x) = 7,
at x = 15, Purple (x) = 0
Learn more about graphs on:
Part A:
From the appearance of the figure above, triangle A B C forms a right angle at B with A B and B C being the legs and A C being the hypothenuse.
Given that <span>A B is 20 and B C is 21, by the pythagoras theorem,
Part B:
</span>From the appearance of the figure above, triangle A B C forms a right angle at B with A B and B C as the legs and A C as the hypothenuse.
If this is true, then the measure of angle A B C is 90 degrees.
Part C:
If A E is 10 and A F is half of A C, the special name for segment E F as it relates to triangle A B C is the midsegment.
The midsegment of a triangle is a line segment which joins the midpoints of two sides of the triangle.
Part D:
Given from part C above that line segment EF is a midsegment of triangle ABC, from the triangle midsegment theorem, line segment EF is parallel to side BC.
Thus, line BF is a transverse of parallel lines EF and BC which makes angle EFB alternate to angle FBC.
Since alternate angles are equal, given that angle <span>EFB is 43.6°, then </span>the measure of angle FBC is also <span>43.6° because they are alternate angles.
Part E:
</span><span>If Triangle DCB is congruent to triangle ABC, then angle B is congruent to angle C.
Given from part B that angle B = 90 degrees, then angle C = 90 degrees. Thus, the two adjacent angles of the quadrilateral ABCD = 90 degrees. Whih shows that the shape ABCD is a rectangle.
</span>
From the appearance of the figure above, triangle A B C forms a right angle at B with A B and B C being the legs and A C being the hypothenuse.
Given that <span>A B is 20 and B C is 21, by the pythagoras theorem,
Part B:
</span>From the appearance of the figure above, triangle A B C forms a right angle at B with A B and B C as the legs and A C as the hypothenuse.
If this is true, then the measure of angle A B C is 90 degrees.
Part C:
If A E is 10 and A F is half of A C, the special name for segment E F as it relates to triangle A B C is the midsegment.
The midsegment of a triangle is a line segment which joins the midpoints of two sides of the triangle.
Part D:
Given from part C above that line segment EF is a midsegment of triangle ABC, from the triangle midsegment theorem, line segment EF is parallel to side BC.
Thus, line BF is a transverse of parallel lines EF and BC which makes angle EFB alternate to angle FBC.
Since alternate angles are equal, given that angle <span>EFB is 43.6°, then </span>the measure of angle FBC is also <span>43.6° because they are alternate angles.
Part E:
</span><span>If Triangle DCB is congruent to triangle ABC, then angle B is congruent to angle C.
Given from part B that angle B = 90 degrees, then angle C = 90 degrees. Thus, the two adjacent angles of the quadrilateral ABCD = 90 degrees. Whih shows that the shape ABCD is a rectangle.
</span>