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Lynna [10]
3 years ago
6

(7y^3 - 3y) + (8y^2 - 8y) help combine like terms

Mathematics
2 answers:
defon3 years ago
7 0
Like terms are terms that are the exact same excluding the coefficient.
The answer here would be 7y^3+8y^2-11y
The only like terms here are y. y^3 and y^2 aren't the same because they have different exponents
Mama L [17]3 years ago
4 0
7y^3+8y^2-11y
like terms: y
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A factory's quality assurance specialist can inspect 28 hard drives in 40 minutes. How many minutes will it take the specialist
stiv31 [10]

Answer:

It will take 280minutes to inspect 196 hard drives

Step-by-step explanation:

If. 28hd=40min

Then. 196hd=x. cross multiply

28hdx=7840hdmin

\frac{28hdx}{28hd}  =  \frac{7840hdmin}{28hd}

x=280minutes

6 0
3 years ago
3.76+​(y-​1/​2)/​2 need help noww homework
Zepler [3.9K]

Answer:

351+50y/100

Step-by-step explanation:

4 0
4 years ago
a gazelle can run away from a cheetah with a speed of 35.0 m/s. if the average gazelle has a mass of 40.00 kg, what is the gazel
bezimeni [28]

9514 1404 393

Answer:

  24.5 kJ

Step-by-step explanation:

Kinetic energy is given by the formula ...

  KE = 1/2mv² . . . . . where m = mass

The gazelle's kinetic energy is ...

  KE = 1/2(40 kg)(35 m/s)² . . . . . where m is meters

  = 24,500 J . . . . . . 1 J = 1 kg·m²/s²

  = 24.5 kJ . . . . . . . 1000 J = 1 kJ

7 0
3 years ago
2y + 3y = 4 - 6 - 13
Anvisha [2.4K]

Answer:

y=-3

Step-by-step explanation:

2y+3y=4−6−13

2y+3y=4+−6+−13

(2y+3y)=(4+−6+−13)

5y=−15

5y=−15

y= −3

6 0
3 years ago
Read 2 more answers
Show all work to factor x^4 − 17x^2 + 16 completely.
Dmitrij [34]

Answer:

x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

Step-by-step explanation:

At first, let us find the first two factors of x^{4}-17x^{2} +16

∵ The sign of the last term is positive

∴ The middle signs of the two factors are the same

∵ The sign of the middle term is negative

∴ The middle signs of the two factors are negative

∵ x^{4} = x² × x² ⇒ first terms of the two factors

∵ 16 = -1 × -16 ⇒ second terms of the two factors

∵ x²(-1) + x²(-16) = -x² + -16x² = -17x² ⇒ the value of the middle term

∴ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

Now let us factorize each factor

→ The factors of the binomial a² - b² (difference of two squares) are

   (a - b) and (a + b)

∵ x² - 1 is the difference of two squares

∴ Its factors are (x - 1) and (x + 1)

∵ x² - 16 is the difference of two squares

∴ Its factors are (x - 4) and (x + 4)

∵ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of (x² - 1) and (x² - 16)

∵ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

∴ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of x^{4}-17x^{2} +16

∴  x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

8 0
3 years ago
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