Let f(x) = x2 and g(x) = x − 3. Evaluate the expression.

Mathematics

1 answer:

vesna_86 [32]3 years ago

6 0

Answer:

Step-by-step explanation:

To evaluate (f ￮ g)(x)

Substitute x = g(x) into f(x), that is

f(g(x))

= f(x - 3)

= (x - 3)² ← expand using FOIL

= x² - 6x + 9 → B

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So confused some one help

SOVA2 [1]

Answer:

-2 (filled in circle) to 7 (open circle)

Step-by-step explanation:

for the first equation x must be the equal to or smaller than 6. so -3(-2) equals 6 but anything less than -2, let's say -3(-3), will be BIGGER than six, so -2 including -2 which is a filled in circle.

solving it:

-3(x) $\leq$ 6

$\frac{-3x}{-3} \leq \frac{6}{-3}$

$x\leq -2$

for the second equation x must be smaller than 17. so first you take out + 3 by subtracting it, leaving the equation as 2x<14. 2(7)<14 is NOT true so anything bigger than 7 leaves it as true because 6.98934747483 can still make it true, so anything smaller than 7 which is 7 with a not filled in, or open, circle

solving it:

$2x + 3 (- 3) < 17 (- 3)$