Maggie has 20 ribbons. 2/5 of the ribbons are polka-dotted ribbons. How many ribbons are not polka

Tyler picks 3/3 dozen apples. Olivia picks 5/6 dozen apples. Samantha picks 2/3 dozen apples. Who picks the least number of appl

Kitty [74]

For this case we have the following apple picking options, in dozens:

Tyler:

$\frac {3} {3} = 1$

Tyler picked up a dozen.

Olivia:

$\frac {5} {6} = 0.833$

Olivia collected 0.833 dozen apples.

Samantha:

$\frac {2} {3} = 0.667$

Samantha collected 0.667 dozens of apples.

Thus, it is observed that Samantha collected the least amount of apples.

ANswer:

Samantha

6 0

2 years ago

Ms. Vicker is trying to save enough money to buy her wedding dress at the cost of $1,200. She has $600 saved from her summer sch

sattari [20]

Answer:

The inequality to determine how many hours Ms. Vicker must tutor to have enough money for the dress.

$600 + 10x ≥ $1200

Step-by-step explanation:

From the question, we are told that:

Ms. Vicker is trying to save enough money to buy her wedding dress at the cost of $1,200. She has $600 saved from her summer school job.

The amount to make up to complete her wedding dress = $1200 - $600

= $600

To make the rest of the money, Ms. Vicker plans to tutor for Sylvan at a cost of $10 per hour.

= Number of hours Ms vicker must tutor Sylvan to make $600 is calculated as:

$600/$10 = 60 hours

The inequality to determine how many hours Ms. Vicker must tutor to have enough money for the dress is written as

$600 + 10x ≥ $1200

4 0

2 years ago

Describe whether each equation is true for all one or no values of x

aev [14]

Answer:

I'll gladly answer if you could give more information. All we can see is the question "Describe whether each equation is true for all one or no values of x," so we need some context.

Step-by-step explanation:

We need context to this.

7 0

1 year ago

If the point (2, 5) is a solution to the system of equations shown below, then determine the missing values of b and m. Show how

antoniya [11.8K]

Complete Question:

If the point (2, 5) is a solution to the system of equations shown below, then determine the missing values of b and m. Show how you arrive at your answer.

1. y = 3x + b

2. y = mx + 9

Answer:

1. Intercept, b = -1

2. Slope, m = -2

Step-by-step explanation:

Given the following data;

Points on the line (x, y) = (2, 5)

To find the missing values;

Mathematically, the equation of a straight line is given by the formula;

y = mx + b

Where;

m is the slope.
x and y are the points
b is the intercept.

1. y = 3x + b

Substituting the value of x and y, we have;

5 = 3(2) + b

5 = 6 + b

b = 5 - 6

Intercept, b = -1

2. y = mx + 9

Substituting the value of x and y, we have;

5 = m(2) + 9

5 = 2m + 9

2m = 5 - 9

2m = -4

m = -4/2

Slope, m = -2

6 0

2 years ago

A. Lin is using the diagram to prove the statement, "If a parallelogram has one

BigorU [14]

The congruence of the angles and triangles are proven as follows;

a. The composition angles of FGH are alternate interior angles to the composition angles of angle AHEF

b. The three sides of triangle ∆EHG are congruent to the three sides of triangle ∆GFE, therefore, triangles ∆EHG and ∆GFE are congruent by SSS congruency rule

<h3>What are congruent triangles?</h3>

The lengths of the three sides of triangles that are congruent.

a. The shape of quadrilateral EFGH = A parallelogram

The measure of angle HEF = 90°

Angle HEF = 90°

Angle HEF = Angle HED + Angle DEF

Angle HED is congruent to angle FGD (Alternate interior angles theorem)

Angle HED = angle FGD

Angle DEF is congruent to angle DGH (Alternate interior angles theorem)

Angle DEF = angle DGH

Angle FGH = Angle FGD + Angle DGH

Angle FGH = Angle HED + Angle DEF (Substitution property)

Angle FGH = Angle HEF (Transitive property)

Angle FGH = Angle HEF = 90°

Therefore, the statement that will help prove angle FGH is also a right is that angle FGH is the sum of angles FGD and angle DGH which are alternate interior angles to angles HED and DEF which makes up angle HEF, which is a right angle.

b. The two-column method can be used to prove that triangle EHG and triangle GFE are congruent as follows;

Statement. Reason

EF is congruent to HG. Opposite sides of a parallelogram are congruent

EH is congruent FG Opposite sides of a parallelogram are congruent

EG is congruent to EG Reflexive property of congruency

∆EHG is cong. to ∆GFE SSS, Side-Side-Side, congruency rule

Learn more about the triangle congruency rules here:

brainly.com/question/15338506

#SPJ1

4 0

7 months ago

Maggie has 20 ribbons. 2/5 of the ribbons are polka-dotted ribbons. How many ribbons are not polka - dotted?