Answer:
If B is between A and C, AB = x, BC = 2x + 2, and AC = 14, find the value of x. Then find AB and BC.
Step-by-step explanation:
AB=x
BC = 2x + 2BC=2x+2
AC =14AC=14
Required
Determine x, AB and BC.
Since B is between A and C;
AB + BC = ACAB+BC=AC
Substitute x for AB; 2x + 2 for BC and 14 for AC
x + 2x + 2 = 14x+2x+2=14
3x + 2 = 143x+2=14
Collect Like Terms
3x = 14 - 23x=14−2
3x = 123x=12 '
x = \frac{12}{3}x=
3
12
x = 4x=4
Substitute 4 for x in
AB = xAB=x
BC = 2x + 2BC=2x+2
AB = 4AB=4
BC = 2(4) + 2BC=2(4)+2
BC = 8 + 2BC=8+2
BC = 10BC=10
Answer:
Pretty sure it's (4, -5)
Step-by-step explanation:
If not, shoot me I guess.
R=16
J=32
20+40(which is 20×2)=60
20-4=16
16×2=32
I can figure out this is a frefall motion.
Starting from rest => Vo = 0
Then, use the equation: d = [1/2]gt^2 => t = √(2d/g)
d = width of a black/clear stripe pair = 5cm = 0.05m
g ≈ 10 m/s^2 (the real value is about 9.81 m/s^2)
t =√(2*0.05m/10m/s^2) = 0.1 s
Answer: approximately 0.1 s