All categories

3 years ago

Does anyone know how too do this please I need help

Mathematics

1 answer:

Natasha2012 [34]3 years ago

4 0

Answer:

1: -17

2 : -51

n/3 that is a fraction

2. n*3

You might be interested in

If ac =14 find the value of x then find ab and bc

Igoryamba

Answer:

If B is between A and C, AB = x, BC = 2x + 2, and AC = 14, find the value of x. Then find AB and BC.

Step-by-step explanation:

AB=x

BC = 2x + 2BC=2x+2

AC =14AC=14

Required

Determine x, AB and BC.

Since B is between A and C;

AB + BC = ACAB+BC=AC

Substitute x for AB; 2x + 2 for BC and 14 for AC

x + 2x + 2 = 14x+2x+2=14

3x + 2 = 143x+2=14

Collect Like Terms

3x = 14 - 23x=14−2

3x = 123x=12 '

x = \frac{12}{3}x=

x = 4x=4

Substitute 4 for x in

AB = xAB=x

BC = 2x + 2BC=2x+2

AB = 4AB=4

BC = 2(4) + 2BC=2(4)+2

BC = 8 + 2BC=8+2

BC = 10BC=10

3 0

2 years ago

You start at (3, 0). You move down 5 units and right 1 unit. Where do you end?

nevsk [136]

Answer:

Pretty sure it's (4, -5)

Step-by-step explanation:

If not, shoot me I guess.

8 0

3 years ago

|. Identify the following Pōints of each values.Write your ans

Dmitry_Shevchenko [17]

<h2>✒️VALUE</h2>

$\\ \quad \begin{array}{c} \qquad \bold{Distance \: \green{ Formula:}}\qquad\\ \\ \boldsymbol{ \tt d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}} \end{array}\\ \begin{array}{l} \\ 1.)\: \bold{Given:}\: \begin{cases}\tt D(- 5,6), E(2.-1),\textsf{ and }F(x,0) \\ \tt DF = EF \end{cases} \\ \\ \qquad\bold{Required:}\:\textsf{ value of }x \\ \\ \qquad \textsf{Solving for }x, \\ \\ \tt \qquad DF = EF \\ \\ \implies\small \tt{\sqrt{(x -(- 5))^2 + (0 - 6)^2} = \sqrt{(x - 2)^2 + (0 - (-1))^2}} \\ \\ \implies\tt\sqrt{(x + 5)^2 + 36 } = \sqrt{(x - 2)^2 + 1 } \\ \\ \textsf{Squaring both sides yields} \\ \\ \implies\tt (x + 5)^2 + 36 = (x - 2)^2 + 1 \\ \\ \implies\tt x^2 + 10x + 25 + 36 = x^2 - 4x + 4 + 1 \\ \\ \implies \tt x^2 + 10x + 61 = x^2 - 4x + 5 \\ \\ \implies\tt10x + 4x = 5 - 61 \\ \\ \implies\tt14x = -56 \\ \\ \implies \red{\boxed{\tt x = -4}}\end{array} \\ \\ \\ \\\begin{array}{l} \\ 2.)\: \bold{Given:}\: \begin{cases}\tt P(6,-1), Q(-4,-3),\textsf{ and }R(0,y) \\ \tt PR = QR \end{cases} \\ \\ \bold{Required:}\:\textsf{ value of }y \\ \\ \qquad\textsf{Solving for }y, \\ \\ \qquad\tt PR = QR \\ \\ \implies \tt\small{\sqrt{(0 - 6)^2 + (y - (-1))^2} = \sqrt{(0 - (-4))^2 + (y - (-3))^2}} \\ \\ \implies\tt\sqrt{36 + (y + 1)^2} = \sqrt{16 + (y + 3)^2 } \\ \\ \textsf{Squaring both sides yields} \\ \\ \implies \tt \: 36 + (y + 1)^2 = 16 + (y + 3)^2 \\ \\ \implies\tt 36 + y^2 + 2y + 1 = 16 + y^2 + 6y + 9 \\ \\ \implies \tt \: y^2 + 2y + 37 = y^2 + 6y + 25 \\ \\ \implies \tt \: 2y - 6y = 25 - 37 \\ \\ \implies \tt -4y = -12 \\ \\ \implies\red{\boxed{ \tt y = 3}} \end{array} \\ \\ \\ \begin{array}{l} \\ 3.)\: \bold{Given:}\: \begin{cases}\: A(4,5), B(-3,2),\textsf{ and }C(x,0) \\ \: AC = BC \end{cases} \\ \\ \bold{Required:}\:\textsf{ value of }x \\ \\ \qquad\textsf{Solving for }x, \\ \\ \qquad\tt AC = BC \\ \\ \implies\tt\small{\sqrt{(x - 4)^2 + (0 - 5)^2} = \sqrt{(x - (-3))^2 + (0 - 2)^2}} \\ \\ \implies\tt\sqrt{(x - 4)^2 + 25} = \sqrt{(x + 3)^2 + 4} \\ \\ \textsf{Squaring both sides yields} \\ \\ \implies\tt\:(x - 4)^2 + 25 = (x + 3)^2 + 4 \\ \\ \implies\tt\:x^2 - 8x + 16 + 25 = x^2 + 6x + 9 + 4 \\ \\ \implies\tt\:x^2 - 8x + 41 = x^2 + 6x + 13 \\ \\ \implies\tt-8x - 6x = 13 - 41 \\ \\\implies\tt -14x = -28 \\ \\ \implies\red{\boxed{\tt\:x = 2}} \end{array}$

#CarryOnLearning

#BrainlyMathKnower

#5-MinutesAnswer

7 0

2 years ago

René is twice as old as Jim In four years the sum of their ages is 60 how old are they now

Brrunno [24]

R=16
J=32
20+40(which is 20×2)=60
20-4=16
16×2=32

3 0

3 years ago

How much times does it take for the first black/clear part to fall through the photo gate timer, starting from the rest? Plastic

Alik [6]

I can figure out this is a frefall motion.

Starting from rest => Vo = 0

Then, use the equation: d = [1/2]gt^2 => t = √(2d/g)

d = width of a black/clear stripe pair = 5cm = 0.05m

g ≈ 10 m/s^2 (the real value is about 9.81 m/s^2)

t =√(2*0.05m/10m/s^2) = 0.1 s

Answer: approximately 0.1 s

5 0

2 years ago