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3 years ago

3x + 2y = 8 x=2 can someone please explain this I beg of u

1 answer:

4 0

So if you multiple the 3 by 3 you get 6. Then you subtract by 6 on both sides. Which makes the 8 = 2. Then you divide by 2 to get y by itself. So divide 2 from 2 and y=1. So y doesn’t really equal anything.

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The height of the Eiffel Tower is 1050 feet. From the top, the angle of depression to a soccer ball on the ground is 20 degrees.

mihalych1998 [28]

Since the angle of depression from the Eiffel tower is congruent to the angle of elevation from the soccer ball, the angle of elevation from the soccer field is 20°

Now, we can use the trigonometric function tangent to find the distance from the soccer ball to the base of the Eiffel Tower:
 $tan( \alpha )= \frac{opposite.side}{adjacent.side}$
$tan(20)= \frac{1050}{a}$
$a= \frac{1050}{tan(20)}$
$a=2884.85$

We can conclude that the distance from the soccer ball to the base of the Eiffel Tower is 2884.85 feet.

3 0

3 years ago

F(x) = x^2 + 4x-12

Ahat [919]

Answer:

a) x-intercepts at -6 and 2

b) y-intercept at -12

c) minimum at (-2, -16)

Step-by-step explanation:

8 0

3 years ago

The recycling and reuse industry employs approximately 1,025,000 more workers than the waste management industry. Together they

NARA [144]

Answer:

Step-by-step explanation:

The recycling and reuse industry employs approximately 1,025,000 more workers than the waste management industry. This means that

Number of workers employed by The recycling and reuse industry = the number of workers employed by the waste management industry + 1,025,000

Let y = the number of workers employed by the waste management industry. Therefore

x = y + 1,025,000 - - - - - - 1

Since total = 1,275,000

x + y = 1,275,000 - - - - - - -2

Substituting equation 1 into equation 2, it becomes

y + 1,025,000 + y = 1,275,000

2y = 1,275,000 - 1,025,000

y = 250000/2 = 125000

x = y + 1,025,000 = 125000 + 1,025,000 = 1150000

The recycling and reuse industry employs 1150000 workers

The waste management industry employs 125000 workers

7 0

4 years ago

What is 8 3/4 - 7 1/2

lara31 [8.8K]

let's firstly convert the mixed fractions to improper fractions and then subtract, bearing in mind that the LCD of 4 and 2 is 4.

$\bf \stackrel{mixed}{8\frac{3}{4}}\implies \cfrac{8\cdot 4+3}{8}\implies \stackrel{improper}{\cfrac{35}{4}}~\hfill \stackrel{mixed}{7\frac{1}{2}}\implies \cfrac{7\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{15}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{35}{4}-\cfrac{15}{2}\implies \stackrel{\textit{using the LCD of 4}}{\cfrac{(1)35~~-~~(2)15}{4}}\implies \cfrac{35-30}{4}\implies \cfrac{5}{4}$

6 0

3 years ago

Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips.Urn II contains three red

lorasvet [3.4K]

Answer:

$P(R_{2}) =\frac{10}{15} = 0.667$

Step-by-step explanation:

Step 1: Understanding the possible events

Selecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be completed in two ways:

A. Selecting a red chip from Urn I and adding it to Urn II and then selecting a red chip from Urn II

B. Selecting a white chip from Urn I and adding it to Urn II and then selecting a red chip from Urn II

Therefore total probability is:

$P(R_{2}) = P(A) + P(B)$

Step 2: Probability of selecting either chip from Urn I

Urn I contains 2 reds and 4 white chips, that gives a total of 6 chips.

$P(R_{1}) = \frac{2}{6} =\frac{1}{3}$

$P(W_{1}) = \frac{4}{6} =\frac{2}{3}$

Step 3: Probability of selecting a red chip from Urn II

Urn II originally contains 3 reds and 1 white chip, that gives a total of 4 chips.

Remember: Once a chip is added from Urn I to Urn II the total number of chips will increase in the Urn II

Case 1: When a red chip is added from Urn I to Urn II

Red chips = 4

White chips = 1

Total Chips = 5

$P(R_{2_1}) = \frac{4}{5}$

Case 2: When a white chip is added from Urn I to Urn II

Red chips = 3

White chips = 2

Total Chips = 5

$P(R_{2_2}) = \frac{3}{5}$

Therefore the total Probability of selecting a chip from Urn I and then adding that chip to Urn II and then selecting a red chip from Urn II can be calculated as:

$P(R_{2}) = P(A) + P(B)$

$P(R_{2}) = P(R_{1}) . P(R_{2_1}) + P(W_{1}) . P(R_{2_2})$

$P(R_{2}) =\frac{1}{3} . \frac{4}{5} + \frac{2}{3} .\frac{3}{5}$

$P(R_{2}) =\frac{4}{15} + \frac{2}{5}$

$P(R_{2}) =\frac{10}{15} = 0.667$

8 0

3 years ago