3 years ago

1 pair of opposite sides that are parallel

1 answer:

4 0

A trapezoid has only 1 pair of parallel sides the other 2 sides will join at some point the other 2 sides will never touch so they are parallel.

Hope that helps.

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If x=0. Find the value of 8x-2(6-x)

Harrizon [31]

Answer:

-12

Step-by-step explanation:

8x - 2(6 - x)

Substitute 0 for each x

8*0 - 2(6 - 0)

Solve.

0 - 2*6

0 - 12

-12

7 0

3 years ago

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You spin the spinner shown below once. Each sector shown has an equal area.

a_sh-v [17]

Answer: P(not shaded sector) = 0.50

Step-by-step explanation:

Since we have given that

Number of shaded parts = 6

Number of unshaded parts = 6

Total parts = 6+6 = 12

So, Probability of getting not shaded sector is given by

$\dfrac{6}{12}\\\\=\dfrac{1}{2}\\\\=0.50$

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8 0

3 years ago

How do u do this ? I'm so confused I really need help

Art [367]

Well what do u need help with can u explain?

5 0

3 years ago

A rectangle has a height of 6k3 and a width of 2k2 + 4k +5.

Trava [24]

Answer: $12k^5+24k^4+30k^3$

Step-by-step explanation:

Given : The height of the rectangle = $6k^3$

The width of the rectangle = $2k^2+4k+5$

Formula : Area = height x width

Therefore , the area of triangle in terms of polynomial will be :

$6k^3\times( 2k^2+4k+5)\\\\= 6k^3(2k^2)+6k^3(4k)+6k^3(5)\ \ [\text{Using Distributive property}]\\\\=12k^{3+2}+24k^{3+1}+30k^3\ \ [\text{Using exponents rule}:\ a^n\times a^m=a^{n+m}]\\\\=12k^5+24k^4+30k^3$

Hence, the area of the entire rectangle = $12k^5+24k^4+30k^3$

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3 years ago

I'LL GIVE BRAINLIEST!!!!!!!!!!

Xelga [282]

Answer:B.

Step-by-step explanation:

7 0

2 years ago

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