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guajiro [1.7K]
2 years ago
9

Rectangle area w algebra step by step explanation please :)

Mathematics
1 answer:
Natalija [7]2 years ago
8 0

We know that the area is 20.

Since 20 is a small number: lets list out possible combinations of lengths and widths.

1 * 20

2 * 10

4 * 5

L = 7 + 3w

lets see which on makes sense.

L = 7 + 3w

20 = w7 + 3w^2

3w^2 + 7w -20 = 0

(3w - 10)(w - 2)

w can equal 10/3 or 2.

So the dimensions: are Width = 2 Length = 10

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Y= -2x^3 is the answer
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4n - 2n = 4<br><br>what's the answer for this ?
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Hey if you're willing to help me with this, it will be very much appreciated, thanks maties and mates.
Nastasia [14]

Answer:

Width=37in

Length=55in

Step-by-step explanation:

Let x in be the width dimension, the length dimension will be x+18 in. Area of a rectangle is calculated as A=lw. Given  the area as2143 sq in, x can be calculated as:

Area= x(18+x)\\\\=18x+x^2\\\\

#Substitute for every x in our function to find the true value of x:

x=37\\\\A=x^2+18x\\\\=37^2+18\times37\\\\=2035 \ in^2#l=37+18=55in

for x=38:

x=38\\\\A=x^2+18x\\\\=38^2+18\times38\\\\=2128 \ in^2#l=38+18=56in

For x=39:

x=39\\\\A=x^2+18x\\\\=39^2+18\times39\\\\=2223 \ in^2#l=39+1854in

From the calculations above, A television with a width of 37 in and length 55in has its area closest to 2143 sq in.

4 0
2 years ago
18 points - Qu. If 16 whole numbers factor into 120. You will see how 32 whole numbers factor into 1200 what does the same princ
alexandr402 [8]

Explanation:

<em>Your premise and conclusion are both incorrect</em>.

120 has the prime factorization ...

  120 = 2³ × 3 × 5

The exponents of the prime factors are {3, 1, 1}. The number of divisors of 120 is the product of the increments of these numbers: (3+1)(1+1)(1+1) = 4·2·2 = 16.

120 has 16 natural-number divisors

__

1200 has the same prime factor and two more: 2·5, so the factorization is ...

  1200 = 2⁴ × 3 × 5²

These exponents are {4, 1, 2} and the product of their increments is 5·2·3 = 30.

1200 has 30 natural-number divisors.

__

When a number is multiplied by 2, its number of natural-number divisors will be (n+1)/n times the previous number of divisors, where n is the increment of the exponent of 2 that is a factor of the original number.

For 120, 2^3 is the power of 2 that is a factor. So, multiplying the number by 2 multiplies the number of divisors by (4+1)/4 = 5/4.

240 will have 20 divisors versus the 16 that 120 has.

Likewise, multiplying this number (240) by 5 will multiply its number of divisors by (2+1)/(1+1) = 3/2, where 1 is the power of 5 that is a factor of 240.

1200 will have 20(3/2) = 30 divisors, versus the 20 that 240 has, or the 16 that 120 has.

__

<em>Summary</em>

The number of divisors of an integer is the product of the increments of the exponents of its prime factors.

_____

<em>For reference</em>

Here are the divisors of 120:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

Here are the divisors of 240:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240

Here are the divisors of 1200:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 25, 30, 40, 48, 50, 60, 75, 80, 100, 120, 150, 200, 240, 300, 400, 600, 1200

7 0
3 years ago
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