The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
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Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Given:
square shape
Perimeter 28 feet
Find its area
A square has 4 equal sides, so perimeter is 4a
Perimeter = 4a
28 ft = 4 a
28 ft / 4 = a
7 = a
One side of the the square is 7 ft.
Area of a square is the measure of one side raised to the power of 2.
A = a²
A = (7 ft)²
A = 49 ft²
Answer:
can you explain this so I can help you with this
He needs 4 boxes :)
Dozen= 12
48 ÷12=4
Answer:
rocky???
Step-by-step explanation:
5/2 3/8
