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4 years ago

What is gk can you please solve for gk

Mathematics

1 answer:

IgorC [24]4 years ago

6 0

The triangles GJK and FGH are congruent to each other.

We can then set up a ratio between the sides of the two triangles.

11/12 = x/8; x=GK
x=7.3333...

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In circle O below, AB is a diameter and m

Neko [114]

Answer:

i don't know

Step-by-step explanation:

i seriously don't know

4 0

3 years ago

Can somebody give me a link to Maths Progress Core 2 active learn

ella [17]

Just get guath math it’s free and give every answer

6 0

3 years ago

How is the graph of Y = log(x) transformed to produce the graph of Y = log(2x)+3?

Troyanec [42]

Answer:

<h2>The required transformation is $X = 2x \times10^{3}$ and Y = y</h2>

Step-by-step explanation:

Transformation means we need to shift the origin to a new position.

Sometimes we also needs to rotate the axis es through some angle.

We need to find the transformation so that, log(X) = log(2x)+3.

$log(X) = log(2x)+3\\ log(\frac{X}{2x}) = 3\\\frac{X}{2x} = 10^{3} \\X = 2x \times10^{3}$

Hence the transformation will be $X = 2x \times10^{3}$ and Y = y.

5 0

3 years ago

what two- dimensional shape is formed by a cross section of the cube shown if the cross section passes through the midpoints of

Nostrana [21]

<h2>Answer:</h2>

C= equilateral triangle

<h2>Step-by-step explanation:</h2>

To find this answer we need to know what a cube is. A cube is a prism whose sides all have the same length. It's something like the three dimensional version of a square. In the figure below, we have labeled each length of the cube as $x$ . Also, the vertex we taken is in blue color, so we need to find each side length of the triangle. Since the cross section passes through the midpoints of three edges that intersect at the same vertices of the cube, then:

$L_{1}=\sqrt{(\frac{x}{2})^2+(\frac{x}{2})^2} \\ \\ L_{1}=\sqrt{\frac{x^2}{4}+\frac{x^2}{4}} \\ \\ L_{1}=\sqrt{\frac{2x^2}{4}} \\ \\ L_{1}=\sqrt{\frac{x^2}{2}} \\ \\ L_{1}=\frac{x}{\sqrt{2}} \\ \\ L_{1}=\frac{x}{\sqrt{2}}\frac{\sqrt{2}}{\sqrt{2}} \\ \\ L_{1}=\frac{\sqrt{2}x}{2}$

Since this is a cube, then it is true that:

$L_{1}=L_{2}=L_{3}=\frac{\sqrt{2}x}{2}$

<em>Since the side lengths have the same value, this is an equilateral triangle.</em>

4 0

4 years ago

Y=-6x-5 x and y intercept form

Elina [12.6K]

Y = -6x - 5

y intercept = -5

Now solve for x.
y = -6x - 5
-6x = y + 5
x = -1/6y - 5/6

x intercept = -5/6

4 0

3 years ago

Read 2 more answers