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3 years ago

Determine whether the following relation represents a function.

Mathematics

2 answers:

My name is Ann [436]3 years ago

7 0

The domain isn't repetitive so it's function.

Domain of Relation is {-9,-2,-7,-5,-4,-8}. There are no same domains or repetitive so It's a function.

Softa [21]3 years ago

3 0

Answer:

yes

Step-by-step explanation:

Each input value only goes to one output value so the relation is a function

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What is the missing exponent of 32=2?

MrRa [10]

32 = 2^5 <==== my answer is too short..lol

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3 years ago

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The product of a number and ten is twelve more than the product of the number and five-eighths.

ra1l [238]

Let the unknown number be x.

Given,

$10 * x = 12 + \frac{5}{8} * x$

$10x = 12 + \frac{5x}{8}$

$10x - \frac{5x}{8} = 12$

$\frac{(10x*8)-5x}{8} = 12$

$80x-5x =12*8$

$75x = 96$

x = $\frac{96}{75}$ = 1.28

Hence, the number is 1.28

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4 years ago

Fred flips a coin, spins the spinner, and rolls a standard number cube. Find the probability that the coin will show tails, the

Inessa05 [86]

Answer:

The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is $\frac{4}{3}$

Step-by-step explanation:

Given : Fred flips a coin, spins the spinner, and rolls a standard number cube.

To find : The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three ?

Solution :

First we find probability one by one,

1) Flips a coin - Head, Tail

Total number of outcome = 2

Favorable outcome (getting a tail) = 1

Probability that the coin will show tails is $P(T)=\frac{1}{2}$

2) Spins the spinner - yellow, green, blue

Total number of outcome = 3

Favorable outcome (land on yellow or green) = 2

Probability that the spinner will land on yellow or green $P(S)=\frac{2}{3}$

3) Rolls a standard number cube - 1,2,3,4,5,6

Total number of outcome = 6

Favorable outcome (show a three) = 1

Probability that the cube will show a three $P(C)=\frac{1}{6}$

The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is

$P=P(T)+P(S)+P(C)$

$P=\frac{1}{2}+\frac{2}{3}+\frac{1}{6}$

$P=\frac{3+4+1}{6}$

$P=\frac{8}{6}$

$P=\frac{4}{3}$

Therefore, The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is $\frac{4}{3}$

5 0

3 years ago

An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

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3 years ago

REALLY NEED HELP <br> What is the slope of the given line??

Montano1993 [528]

Answer:

Step-by-step explanation:

slope is rise over run

6/2 simplifyed is 3/1 or just 3

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3 years ago