Answer:
The dimensions are 50 and 100 square foot
Step-by-step explanation:
Let x = length of fenced side parallel to the side that borders the playground
y = length of each of the other two fenced sides
Then, x + 2y = 200
<=> x = 200-2y
The Area = xy = y(200-2y)
The dimensions of the playground that will minimize the homeowner's total cost for materials when the area of the playground is maximum. He can cover more area but with the same cost.
The graph of the area function is a parabola opening downward.
The maximum area occurs when y = -200/[2(-2)] = 50
=> x = 100
So the dimensions are 50 and 100 square foot
Let f(x)=ax+b
11a+b=23.55
12a+b=25.35
solve: a=1.8 b=3.75
so ..
f(x)=1.8x+3.75
if x=31 , f(x)=59.55
Answer:
B
Step-by-step explanation:
It is right
500 + 30g <span>≤ 8000
30g </span><span>≤ 7500
g </span><span>≤ 250</span>
Answer:
22
Step-by-step explanation:
Given that T is the midpoint of line PQ, segments PT = 5x + 2, and TQ = 7x - 6 that are formed would be equidistant or congruent. PT = TQ.
Therefore:
Let's find the value of x
Rearrange the equation, so that the terms having x would be on your left, while those without x would be on your right.
Divide both sides by -2
Plug in the value of x into the expression, 5x + 2, to find PT.
PT = 5(4) + 2 = 22.
