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abruzzese [7]
3 years ago
9

Orlando has a loan with an effective interest rate of 7. 918%, compounded annually. Which of the following must be true? I. In t

he effective rate formula, n is equal to one. II. The nominal rate is 7. 918%. III. The Federal Funds Rate is static. A. I and II b. II only c. III only d. I, II, and III.
Mathematics
1 answer:
svetlana [45]3 years ago
4 0

The correct option is B,  II. only.

Given to us,

I. In the effective rate formula, n is equal to one.

Effective interest rate formula,

r = (1 + \dfrac{i}{n} )^n - 1.

where,

r is the effective interest rate,

i is the stated interest rate,

n is the number of compounding periods per year.

According to the question the compounding periods per year is not given to us. Also, loans are taken for a longer period of time.

Thus, we can conclude that statement is false.

II. The nominal rate is 7. 918%.

nominal rate = real interest rate + inflation rate,

but as it is not mentioned in the question about the inflation rate. the statement is true to us. Assuming the inflation rate is 0%.

Thus, we can conclude that statement is true.

III. The Federal Funds Rate is static.

This statement is false, as the no information is given about this statement also this can not be concluded through assumption.

Thus, we can conclude that statement is false.

Hence, The correct option is B,  II. only.

To know more visit:

brainly.com/question/15846526

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Answer:

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Step-by-step explanation:

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Hatshy [7]

Answer:

(x - 1)²/4² - (y - 2)²/2² = 1 ⇒ The bold labels are the choices

Step-by-step explanation:

* Lets explain how to solve this problem

- The equation of the hyperbola is x² - 4y² - 2x + 16y - 31 = 0

- The standard form of the equation of hyperbola is

  (x - h)²/a² - (y - k)²/b² = 1 where a > b

- So lets collect x in a bracket and make it a completing square and

  also collect y in a bracket and make it a completing square

∵ x² - 4y² - 2x + 16y - 31 = 0

∴ (x² - 2x) + (-4y² + 16y) - 31 = 0

- Take from the second bracket -4 as a common factor

∴ (x² - 2x) + -4(y² - 4y) - 31 = 0

∴ (x² - 2x) - 4(y² - 4y) - 31 = 0

- Lets make (x² - 2x) completing square

∵ √x² = x

∴ The 1st term in the bracket is x

∵ 2x ÷ 2 = x

∴ The product of the 1st term and the 2nd term is x

∵ The 1st term is x

∴ the second term = x ÷ x = 1

∴ The bracket is (x - 1)²

∵  (x - 1)² = (x² - 2x + 1)

∴ To complete the square add 1 to the bracket and subtract 1 out

   the bracket to keep the equation as it

∴ (x² - 2x + 1) - 1

- We will do the same withe bracket of y

- Lets make 4(y² - 4y) completing square

∵ √y² = y

∴ The 1st term in the bracket is x

∵ 4y ÷ 2 = 2y

∴ The product of the 1st term and the 2nd term is 2y

∵ The 1st term is y

∴ the second term = 2y ÷ y = 2

∴ The bracket is 4(y - 2)²

∵ 4(y - 2)² = 4(y² - 4y + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out

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∴ 4[y² - 4y + 4) - 4]

- Lets put the equation after making the completing square

∴ (x - 1)² - 1 - 4[(y - 2)² - 4] - 31 = 0 ⇒ simplify

∴ (x - 1)² - 1 - 4(y - 2)² + 16 - 31 = 0 ⇒ add the numerical terms

∴ (x - 1)² - 4(y - 2)² - 16 = 0 ⇒ add 14 to both sides

∴ (x - 1)² - 4(y - 2)² = 16 ⇒ divide both sides by 16

∴ (x - 1)²/16 - (y - 2)²/4 = 1

∵ 16 = (4)² and 4 = (2)²

∴ The standard form of the equation of the hyperbola is

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