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2 years ago

6

Please help!!!

1 answer:

lilavasa [31]2 years ago

5 0

The answer to question #1 is x = 7

For a line to be parallel to x = 8, it has to start with x = some number. Such a line would have an undefined slope.

Now, x = y is a line that goes through the origin. It has a slope of 1.

The answer to question #2 is y = 7

If a line is perpendicular to x = some number, then it has to be y = some number.

And this perpendicular line has to go through the point (4,7). So what is the y-value of this point, since the equation starts with y? The y-value is 7. So the equation has to be y = 7

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Can you help ASAP......

viva [34]

Answer:

I don't know the answer BUT you can go to tutor.com or khan academy. Both are safe websites that can help you online. I suggest tutor.com since it's safe.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Given n//p m<2=50 degrees what is m<7?

Bogdan [553]

Answer: m∠7=130°

Step-by-step explanation:

If two parallel lines are cut by another line (transversal), each one will have four angles surrounding the intersection.

By definition, the adjacent angles of each parallel line, are supplementary, this means that they add up 180°.

Then, if m∠2=50°, then m∠3 is:

m∠3 $=180-50=130$ °

By definition, the angles that are in the same relative position are know as corresponding angles and they are congruent.

Therefore:

m∠3=m∠7

m∠7=130°

3 0

2 years ago

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Please write out the problem on paper

skad [1K]

Your answer will be n5

7 0

2 years ago

In 2000 the total amount of gamma ray bursts was recorded at 6.4 million for a city. In 2005, the same survey was made and the t

ratelena [41]

Let's assume

It started in 2000

so, t=0 in 2000

$P_0=6.4million$

we can use formula

$P(t)=P_0 e^{rt}$

we can plug value

$P(t)=6.4 e^{rt}$

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million

so, at t=2005-2000=5

P(t)=7.3 million

we can plug value and then we can solve for r

$7.3=6.4 e^{r*5}$

$r=0.02632$

now, we can plug back

$P(t)=6.4 e^{0.02632t}$

now, we have

P(t)=1 billion =1000 million

so, we can set it and then we can solve for t

$1000=6.4 e^{0.02632t}$

$t=191.924$

approximately

$t=192$

Year is 2000+192

year is 2192................Answer

4 0

2 years ago

find the smaller of 2 consecutive integers,x, if the sum of the smaller and 6 times the larger is -29

AnnyKZ [126]

Answer:- The smaller integer is -5.

Explanation:-

Let the first consecutive integer be x and the second consecutive integer be x+1.

According to the given question:-

x+6(x+1)= -29

⇒x+6x+6= -29 [distributive law]

⇒x+6x= -29-6 [subtract 6 on the both sides]

⇒7x= -35 [combining like terms ]

⇒x= -5 [dividing 7 on both sides]

Thus the smaller integer =x= -5

larger integer =x+1= -5+1= -4

3 0

3 years ago