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3 years ago

PLEASE HELP Which function represents a line with a slope of negative 4 and a y-intercept of negative 2

Mathematics

1 answer:

ivann1987 [24]3 years ago

6 0

Answer:

Step-by-step explanation:

both the slope and y intercept are negative so therefore it has to be -4x because that is what it said the y intercept is negative e so -2 so the answer is C)y=-4x-2

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5 + 0.55x = 10 + 0.75x pls help and explain

inysia [295]

Step-by-step explanation:

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3 0

2 years ago

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Calculate the distance between the points!

Nuetrik [128]

Answer:

6.71

Step-by-step explanation:

c= $\sqrt{}$ (3-9)^2+(-1+4)^2

c=√36+9

c=6.71

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2 years ago

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A circle has a diameter with endpoints at (6, 5) and (8, 5). Write the equation for the circle.

mario62 [17]

Answer:

$(x-7)^2+(y-5)^2=1$

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

Center of the circle:

The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

$(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$(x_m, y_m) = \left(\dfrac{6+8}{2},\dfrac{5+5}{2}\right)$

$(x_m, y_m) = (7,5)$

This is the center coordinate of our circle.

Radius:

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}$

$r = \sqrt{(6-7)^2+(5-5)^2}$

$r = \sqrt{1^2}$

$r = 1$

Equation of the circle:

The equation is written as:

$(x-a)^2+(y-b)^2=r^2$

here, (a,b) are the center points of the circle

in our case this is $(a,b)=(x_m,y_m)=(7,5)$

and r = 1

$(x-7)^2+(y-5)^2=1^2$

$(x-7)^2+(y-5)^2=1$

This is the equation of the circle!

3 0

2 years ago

Compare -3.6 and 1.2.

jasenka [17]

Answer:

-3.6 is a negative number compared to 1.2. 1.2 is -3 times less than -3.6. -3.6 is -3 times more than 1.2

Step-by-step explanation:

(can I get brainliest)

8 0

2 years ago

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state the domain, the range, and the intervals on which function is increasing, decreasing, or constant in interval notation

erma4kov [3.2K]

Answer:

domain (-∞, ∞)
range (-∞, 4]
increasing (-∞, 0)
decreasing (0, ∞)
constant (only at x=0, not on any interval)

Step-by-step explanation:

The graph is of the equation y = -x^2 +4. It is a polynomial of even degree, so has a domain of all real numbers: (-∞, ∞).

The vertical extent of the graph includes y=4 and all numbers less than that:

range: (-∞, 4]

The graph is increasing to the left of its vertex at x=0, decreasing to the right.

increasing (-∞, 0); decreasing (0, ∞)

There is no interval on which the function is constant. It has a horizontal tangent at x=0, but a single point does not constitute an interval.

8 0

2 years ago