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Ann [662]
3 years ago
15

The tens digit of a two-digit number is twice the units digit. If the digits are reversed, the new number is 36 less than the or

iginal number. Find the number.
Mathematics
1 answer:
Ludmilka [50]3 years ago
7 0
Try this solution:
let the unknown two-digits number be 'xy'.
Then it is possible to write any two-digit number as 10x+y, where x - the tens digit and y - the unit digit.
Using the rule described above the phrase 'the tens digit of a number is twice the units digit' may be written as x=2y.
Using the same rule the phrase 'if the digits are reversed, the new number is 36 is less than the original number' may be written as (10x+y)-(10y+x)=36.
These two equations may be resolved as system of two equations:
\left \{ {{x=2y} \atop {10x+y-(10y+x)=36}} \right. \ =\ \textgreater \  \  \left \{ {{x=8} \atop {y=4}} \right.
Check: the original number is 84, the new number is 48; difference is 84-48=36.

answer: 84
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

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This means that 100 - 5 = 95% pass in at least one, which means that P(A \cup B) = 0.95

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3000 is 60% of the total t. So

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Step-by-step explanation:

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