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Ann [662]
3 years ago
15

The tens digit of a two-digit number is twice the units digit. If the digits are reversed, the new number is 36 less than the or

iginal number. Find the number.
Mathematics
1 answer:
Ludmilka [50]3 years ago
7 0
Try this solution:
let the unknown two-digits number be 'xy'.
Then it is possible to write any two-digit number as 10x+y, where x - the tens digit and y - the unit digit.
Using the rule described above the phrase 'the tens digit of a number is twice the units digit' may be written as x=2y.
Using the same rule the phrase 'if the digits are reversed, the new number is 36 is less than the original number' may be written as (10x+y)-(10y+x)=36.
These two equations may be resolved as system of two equations:
\left \{ {{x=2y} \atop {10x+y-(10y+x)=36}} \right. \ =\ \textgreater \  \  \left \{ {{x=8} \atop {y=4}} \right.
Check: the original number is 84, the new number is 48; difference is 84-48=36.

answer: 84
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they drove 10 miles less on the first day

2,650 - 10 = 2,640

They drove 2,640 miles on the first day.

Hope this helps. :)

7 0
3 years ago
What is the answer to 66- = R2
mars1129 [50]

Answer:

R=-33

Step-by-step explanation:

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The hour hand on a clock is 4 cm long, and the minute hand is 10 cm long. What is the exact distance between the tips of the han
Allushta [10]

Answer:

2 sqrt(19)

Step-by-step explanation:

We know that the angle between the two hands

360 /12 *2 = 60 degrees

We divide by 12 because there are 12 number and multiply by 2 because there are 2 number between 10 and 12

This is a triangle where we know 2 sides and the angle between them.

We can use the law of cosines to determine the third side

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4 0
2 years ago
Which expression is equivalent to √48x5, if x> 0?
Lerok [7]

Answer:

C. 4x²√(3x)

Step-by-step explanation:

if x > 0

\sqrt{48x^{5}} =\sqrt{48} \times \sqrt{x^{5}}

          =\sqrt{16\times 3} \times \sqrt{x^{4}\times x}

          =\sqrt{16} \times \sqrt{3} \times \sqrt{x^{4}} \times \sqrt{x}

          =4\times \sqrt{3} \times \sqrt{\left( x^{2}\right)^{2}  } \times \sqrt{x}

          =4\times \sqrt{3} \times x^{2}\times \sqrt{x}

          =4\times x^{2} \times  \sqrt{3} \times \sqrt{x}

          =4\times x^{2}\times \sqrt{3x}

8 0
1 year ago
Given that a = 1, b = 2, and C = -3, evaluate<br>ab²- ac²/ 2bc​
Firlakuza [10]

Answer:

5/12

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