3 years ago

Evaluate: log16^64 •1/3 •2/3 •3/2

1 answer:

8 0

Answer: B: 3/2

Step-by-step explanation:

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andriy [413]

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satela [25.4K]

$\sqrt{a}=b\iff b^2=a\ for\ a\geq0\ and\ b\geq0\\\\\dfrac{4}{-3\sqrt{64}}=\dfrac{\not4^1}{-3(\not8_2)}=-\dfrac{1}{6}$

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Nikolay [14]

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Step-by-step explanation:

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DIA [1.3K]

<h2>Answer:</h2><h2>14</h2><h2></h2><h2>Hope this helps!!</h2>

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