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seraphim [82]
4 years ago
11

What is the solution to the equation

Mathematics
1 answer:
zimovet [89]4 years ago
7 0
The answer is S: -2

If you need me to show work just comment
You might be interested in
Kareem took 4 2/5 hours to clean the bathroom. Then he took 2 1/4 hours to clean the den. How much total time did Kareem take to
nika2105 [10]

Answer:

  6 13/20 hours

Step-by-step explanation:

Addition of fractions requires they be expressed using a common denominator. Here, that will be 5·4 = 20, and the two fractions can be written as ...

  2/5 = 8/20

  1/4 = 5/20

Then the sum of the mixed numbers is ...

  (4 2/5) +(2 1/4) = (4 +2) +(2/5 +1/4) = 6 +(8/20 +5/20)

  = 6 13/20

It took Kareem 6 13/20 hours to clean the two rooms.

6 0
3 years ago
heather works as a waitress at her family restaurant. she works 2 hours every morning during the breakfast shift and returns to
Marrrta [24]

Answer:

3.6 hours per evening shift

Step-by-step explanation:


5 0
3 years ago
Quadratic Formula to solve the equation x^2- 4x = - 7
mylen [45]

roots of the equation x^2- 4x = - 7 are  2+3i and 2-3i

What are the natures of root of quadratic equation?

Case I: 4ac > b^2

The roots of the quadratic equation ax^2 + bx + c = 0are real and unequal when a, b, and c are real numbers, a 0, and the discriminant is positive.

Situation II:  b^2-4ac =0

The roots and of the quadratic equationax^2 + bx + c = 0  are real and equal when a, b, and c are real numbers, a 0, and the discriminant is zero.

Case III: b^2-4ac<0

The quadratic equation ax^2 + bx + c = 0 has roots when a, b, and c are real numbers, a 0, and the discriminant is negative, but these roots are not equal and are not real. We refer to the roots in this instance as fictitious.

Case IV: Perfect square and b^2 - 4ac > 0

The roots of the quadratic equation ax^2 + bx + c = 0  are real, rational, and unequal when a, b, and c are real numbers, a 0, and the discriminant is positive and perfect square.

Quadratic Formula x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}

x^2- 4x = - 7

x^2-4x+7=0

Here a = 1 , b = -4 , c = 7

using quadratic formula

x={\frac {-(-4)\pm {\sqrt {(-4)^{2}-4(1)(7)}}}{2(1)}}

x={\frac {4\pm {\sqrt {-12}}}{2}}

x={\ {2\pm {\ 3i}}

Learn more about quadratic equation from the link below

brainly.com/question/2279540

#SPJ1

8 0
1 year ago
Using the completing-the-square method, find the vertex of the function f(x) = 2x2 − 8x + 6 and indicate whether it is a minimum
german

Answer:

minimum at (2, - 2 )

Step-by-step explanation:

The equation of a parabola in vertex form is

f(x) = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

If a > 0 then the vertex is a minimum

If a < 0 then the vertex is a maximum

Given

f(x) = 2x² - 8x + 6 ← factor out 2 from the first 2 terms

     = 2(x² - 4x) + 6

To complete the square

add/ subtract ( half the coefficient of the x- term)² to x² - 4x

f(x) = 2(x² + 2(- 2)x + 4 - 4) + 6

     = 2(x - 2)² - 8 + 6

     = 2(x - 2)² - 2 ← in vertex form

with vertex = (2, - 2) and a > 0

Thus minimum at (2, - 2 )

5 0
4 years ago
The heights of a group of boys and girls at a local middle school are shown on the dot plots below.
netineya [11]

<u>Answer:</u>

The most appropriate answer option is D) The girls are generally taller than the boys.

<u>Step-by-step explanation:</u>

A) The shortest boy is taller than the shortest girl:

The shortest guy is not taller than the girl so its false.

B) The range for the girls is greater than the range for the boys:

Range for girls = 56 - 44 = 12

Range for boys = 54 - 41 = 13

C) There is an outlier in the data for the boys, but not for the girls:

It is present in both.

D) The girls are generally taller than the boys:

Average height of boys = \frac{(41)+(44\times3)+(46\times3)+(48\times2)+(50\times3)+(52\times)+(54\times4)}{20} = 49.05

Average height of girls = \frac{(44\times2)+(46\times2)+(48)+(50\times3)+(52\times4)+(54\times3)+(56\times4)}{20} = 50.9

Therefore, the correct answer option is D) The girls are generally taller than the boys.

4 0
3 years ago
Read 2 more answers
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