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3 years ago

(7^3)^-5 Please help! :)

1 answer:

4 0

I believe the answer is 7^-15, here’s a quick explanation:
multiply the exponents, but my answer is for simplifying the expression, i hope it helped!

You might be interested in

What is the slope of the line that passes through the points (-4, -9) and (5, 3)

egoroff_w [7]

Answer:

4/3

Step-by-step explanation:

Moving from (-4, -9) to (5, 3), x (the 'run') increases by 9 from -4 to 5, and y (the 'rise') increases by 12 from -9 to +3. Thus, the slope of the line connecting the two points is

m = rise / run = 12/9 = 4/3

It may help to think of the change in x (9) as the horizontal leg of a right triangle and the change in y (12) as the vertical leg. Then

m = (vertical leg length) / (horizontal leg length) = 12/9 = 4/3

5 0

3 years ago

Circle K has a diameter of 24 inches. Find the exact length of semicircle HJI. In your final answer, include all of your calcula

Svet_ta [14]

A semicircle's perimeter is half the perimeter of the complete circle.

The perimeter of the complete circle is its circumference which is found by the equation: πD.

Then the equation of the perimeter of the semicircle is πD/2

In this case D = 24 in, then the perimeteir is π (24in/2) = 12π in ≈ 37.7 in

Answer: The exact length is 12π inches and the approximate length is 37.7 inches

4 0

4 years ago

Read 2 more answers

PLS HELP ASAP, ILL MARK BRAINLIEST IF ITS A REAL ANSWER. LOOK AT THE PICTURE !

lozanna [386]

Answer:

Step-by-step explanation:

No because if it's 20,000 on 1 it should be 40,000 on 2 but its not so its not proportional

7 0

3 years ago

Find the flux of the vector field F = 〈e-z,4z,6xy) across the curved sides of the surface S = {(x,y,z): z= cos y, lys π, 0sxs4}

Len [333]

I'll go ahead and assume you meant to say that <em>S</em> is the surface given by

$S = \left\{(x,y,z) \mid z = \cos(y)\text{ with } 0\le y\le \pi\text{ and }0\le x\le4\right\}$

This immediately gives us a parameterization for the surface,

$\vec r(x, y) = \left\langle x, y, \cos(y)\right \rangle$

The upward-pointing normal vector to this surface is then

$\vec n = \dfrac{\partial\vec r}{\partial x} \times \dfrac{\partial\vec r}{\partial y} = \left\langle0,\sin(y),1\right\rangle$

Then the flux of $\vec F(x,y,z) = \left\langle e^{-z}, 4z, 6xy\right\rangle$ across <em>S</em> is

$\displaystyle \iint_S \vec F(x,y,z)\cdot\mathrm d\vec s = \int_0^4\int_0^\pi \vec F(x,y,\cos(y))\cdot\vec n\,\mathrm dy\,\mathrm dx \\\\ = \int_0^4\int_0^\pi \left\langle e^{-\cos(y)},4\cos(y),6xy\right\rangle \cdot \left\langle0,\sin(y),1\right\rangle \,\mathrm dy\,\mathrm dx \\\\ = \int_0^4\int_0^\pi (4\sin(y)\cos(y)+6xy)\,\mathrm dy\,\mathrm dx \\\\ = 2 \int_0^4\int_0^\pi (\sin(2y) + 3xy)\,\mathrm dy\,\mathrm dx = \boxed{24\pi^2}$

8 0

3 years ago

Helpppppp now plzzzzzzzzz

WINSTONCH [101]

Getting a new job
Getting a job, birthday

8 0

3 years ago