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Alex
3 years ago
7

A submarine dives 300ft every 2 min. And 6,750ft every 45min. Find the constant rate at which the submarine dives. Give your ans

wer in feet per minute and in feet per hour?
Mathematics
1 answer:
padilas [110]3 years ago
7 0
150 ft per minute and 9,000 feet per hour
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aleksandrvk [35]

Answer: 9 cm

Step-by-step explanation:

By multiplying 5 by 3, you get 15. this would also apply to finding the other side of the rectangle, where you multiply 3 by 3 to get 9.

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Using a multiple of ten for at least one factor write an equation with a product that has four zeros
PtichkaEL [24]

Answer:

The required equation is : 5 · 4000 = 20,000

Step-by-step explanation:

We have to use multiple of 10 for at least one factor.

So, in order to form our equation, we take one factor as 4000 which is a multiple of 10 (10 × 400 = 4000)

And the other condition to form the equation is given that the product should contain 4 zeros, so we need to multiply the first factor 4000 by some number such that the product contains 4 zeros.

Therefore, if we multiply 4000 by 5 we get the product as 20000 which contains 4 zeros.

Hence, 5 × 4000 = 20,000 is our required equation.

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2 years ago
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11111nata11111 [884]

Answer:

simple. y=x+2

Step-by-step explanation:

:) ======

3 0
2 years ago
A newly discovered planet orbits a distant star with the same mass as the Sun at an average distance of 101 million kilometers.
Elden [556K]
Kepler's third law described the relation between semi-major axis (or average distance to the star) and the orbital period (how long it takes to complete one lap) as follows: 
                                           a^3 / p^2 = constant
In the case of our Solar system the constant is 1 
This means that, for this problem:
a^3 / p^2 = 1
p^2 = a^3
p = a^(3/2)
The semi major axis is given as 101 million km. We need to convert this into AU where 1 AU is approximately 150 million Km
101 million Km = (101x1) / 150 = 0.67 AU

Now, we substitute in the equation to get the orbital period as follows:
p = (0.67)^(3/2) = 0.548 earth years
3 0
3 years ago
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