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GREYUIT [131]
3 years ago
14

The president of a certain university receives a salary that is three times the salary of one of the department heads the total

of the two salaries is $190,000, what is the salary of the department head
Mathematics
2 answers:
Alexxx [7]3 years ago
6 0
To determine the salary of the department head, you will create any equation that represents the situation. Equation it will be in terms of S, the salary of one of the department heads.

3s + s = 190000
4s = 190000
s = $47500

The salary of the department head is $47,500.
Mila [183]3 years ago
4 0

Answer:

Step-by-step explanation:

the answer would be 47,500

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Answer: B

Step-by-step explanation:  Length x Width = Area

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How is the series 5+11+17…+251 represented in summation notation?
NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

  • Arithmetic Series

A series that has common difference.

  • Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

5 0
2 years ago
Easiest question in the world no joke this time
Volgvan

Question #25:

One way to solve this is by multiplying the number of packages per serving by the number of guests.

1/4 * 16 = 4 packages to serve 16 guests. This means he doesn't have enough.

A second way to solve this is by diving the number of packages by the number of packages it takes to make on serving.

3 1/2 ÷ 1/4 = 14 guests he can serve. This means he doesn't have enough.

Question #26:

First, find common denominators.

2/3 = 8/12

1/4 = 3/12

Second, subtract.

8/12 - 3/12 = 5/12

Therefore, the tank is 5/12 full at the end of the trip.

Question #27:

1/2 is cut off then 1/3 is cut off. This means 3/6 was cut off to bundle newspapers, then 1/6 was cut off to make parcel. In all, 4/6 was cut off the original string. Afterwards, 2/6 was left over. So, just multiply; 2 * 3 = 6.

Therefore, the original string was as a total of 6 meters.

Best of Luck!

3 0
3 years ago
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