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zvonat [6]
3 years ago
6

If the graph of the function f defined by f(x)= −2x^2+1 is translated vertically downward by 3 units, it becomes the graph of a

function h. How can I find the expression for h(x)?
Mathematics
1 answer:
Katena32 [7]3 years ago
7 0

Answer:

  h(x) = -2x^2 -2

Step-by-step explanation:

You know that translating the point (a, b) vertically downward by 3 units will make it be the point (a, b-3).

The same translation works on the point (x, f(x)), or when a=x and b=f(x). Translated downward by 3 units, the point becomes ...

  (x, f(x) -3)

You want to name this (x, h(x)), so we have ...

  h(x) = f(x) -3

  h(x) = -2x^2 +1 -3 . . . substitute the expression for f(x)

  h(x) = -2x^2 -2 . . . . . simplify

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Functions & (f o g) (#)
sertanlavr [38]
Hello there!

I'm assuming since there is no question, that you want an explanation for composite functions.

Today, I want to introduce you to a very new way of looking at functions. Think of a function as a machine. I'll call this machine f. When you plug something into this machine, it is an x-value. The machine changes the x-value into a new value which is called a y-value. This is how a function works.

With composite functions though, things get a little bit tricky. To make f(g(x)), you need to plug in x into the g machine, and it will give you an output. (y-value) The next thing you do is take that y-value and plug it into the g machine. The g machine then gives you a new value. This value is f(g(x)).

Let's do an example together...
f(x)=3x and g(x)=x²+4
if we want f(g(x)), first plug in x to the g machine. when plugging in x to the g machine, we get x²+4 as given in the question.
Now we must plug in g(x) into the f machine. Since g(x) is x²+4, we just replace x with x²+4.
We get 3(x²+4)
This means that f(g(x))=3(x²+4)

NOTE: If you are seeking help with an actual question, please message me in the comments and I will assist you shortly!

I hope this helps!
Best wishes :)
7 0
2 years ago
Find and sketch the domain of the function. f(x,y)=√(4-x^2-y^2) +√(1-x^2)<br>​
elena55 [62]

Answer:

Hello

Step-by-step explanation:

The domain is limited with 2 lines parallel: -1 ≤ x ≤ 1

and the disk ? (inside of a circle) of center (0,0) and radius 2

dom\ f(x,y)=\{(x,y) \in \mathbb{R} ^2 | \ -1\leq x \leq -1\ and \ ( -\sqrt{4-x^2}  \leq \ y  \leq \sqrt{4-x^2}\  ) \ \}\\

3 0
2 years ago
2. If the diameter of a circle is 2V10, what is the area<br> of the circle.
Sidana [21]
Area is 10pi I think Bc radius is radical 10 Bc 2 radical 10/2 is radical 10. Then we do pi times radical 10 to the second power. Radical 10 to the second power is 10 Bc we remove radical when it is to the second power. Therefore, it becomes 10 times pi or 10pi
6 0
2 years ago
Evaluate the function for the given input values f(x)=3x-1 find f(2) f(2)=
Harman [31]

Answer:

f(2) =5

Step-by-step explanation:

We have a function f(x) = 3x-1

When we find f(2) ,let x=2

f(2) = 3*2-1

      = 6-1

    =5

8 0
3 years ago
What is the degree of vertex A?
GREYUIT [131]

Answer:

  c.  6

Step-by-step explanation:

The degree of a vertex is the number of arc ends that intercept it. (The other end of the arc is irrelevant.)

Vertex A is connected to B (1), D (2), F (1), and itself (2). There are a total of 6 arc ends that meet vertex A. Its degree is 6.

7 0
3 years ago
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