Answer:
108
Step-by-step explanation:
Limit as x approaches 9 of x^2 -81/sqrt of x - 3
First substitute x into the expression
= 9²-81/√9 - 3
= 81-81/3-3
= 0/0 (indeterminate)
Apply l'hospital rule
= lim x -> 9 d/dx(x²-81)/√x - 3
= lim x -> 9 2x/1/2√x
Substitute x = 9
= 2(9)/1/2√9
=18/1/(2(3)
=18 × 6/1
= 108
Hence the limit of the function is 108
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

By substitution, we have that

and

.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
Answer:-19=33y
Step-by-step explanation:
-5-15y-1=14y-32y
-19-15y=18y
18y+15y
-19=33y