Write an equation for a rational function that has a vertical asymptote at x=1 and a hole at x=3

HELPPPPPPPPPPPPPP PLEASE

alukav5142 [94]

Answer:

H

Step-by-step explanation:

educated guess

5 0

3 years ago

The gear ratio of two gears is the ratio of the number of teeth of the larger gear to the number of teeth of the smaller gear. I

VLD [36.1K]

Answer:

24 gear.

Step-by-step explanation:

It is given that $Gear A:Gear B=Gear B:Gear C$ .

$\dfrac{Gear A}{Gear B}=\dfrac{Gear B}{Gear C}$

Gear A = 36 teeth

Gear C = 16 teeth

Let gear B have x teeth.

$\dfrac{36}{x}=\dfrac{x}{16}$

On cross multiplication we get

$36\times 16=x\times x$

$576=x^2$

Taking square root on both sides.

$24=x$

Therefore, gear B have 24 teeth.

6 0

4 years ago

okay everybody ive been answer algebra and there all good answer but nobody seems to say thank you or nothing when there looking

mylen [45]

Answer:

I hate when people do that so I always say thanks when people give legit answers

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A circle has a radius of 9 inches. The Radius is multiplied by 2/3 to form a second circle. How is the ratio of the areas relate

liraira [26]

Answer:

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{r_{1} }{r_{2}}) ^{2}$

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii.

Step-by-step explanation:

Radius of first circle $(r_{1})$ = 9 inches

Area of first circle = $\pi r_{1} ^{2}$

Area of first circle = 9 × 9 × π = 81 π

Now, since the radius is multiplied by 2/3 for from a new circle.

∴ Radius of the second circle = $9 \times \frac{2}{3} = 6\ inches$

Area of second circle = $\pi r_{2} ^{2}$

Area of second circle = 6 × 6 × π = 36 π

Now,

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81\pi }{36\pi }$

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{9}{6}) ^{2} = (\frac{r_{1} }{r_{2}}) ^{2}$

∵ $(r_{1})$ = 9 inches and $(r_{2})$ = 6 inches

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii. i.e., $\frac {radius\ of\ first\ circle)^{2} }{(radius\ of\ second\ circle)^{2} } = \frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)}$

8 0

3 years ago

Solve Quadratic Equations by Factoring:

mr_godi [17]

Answer:

x = 0 or 1
x = ±i/4
x = -5 (twice)

Step-by-step explanation:

Factoring is aided by having the equations in standard form. The first step in each case is to put the equations in that form. The zero product property tells you that a product is zero when a factor is zero. The solutions are the values of x that make the factors zero.

1. x^2 -x = 0

x(x -1) = 0 . . . . . x = 0 or 1

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2. 16x^2 +1 = 0

This is the "difference of squares" ...

(4x)^2 - (i)^2 = 0

(4x -i)(4x +i) = 0 . . . . . x = -i/4 or i/4 (zeros are complex)

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3. x^2 +10x +25 = 0

(x +5)(x +5) = 0 . . . . . x = -5 with multiplicity 2

5 0

3 years ago