The second graph is correct
I’m pretty sure the anser is b
Use distributive property
3(x + 2) = 2(2x + 7)
(3)(x) + (3)(2) = (2)(2x) + (2)(7)
3x + 6 = 4x + 14 |subtract 6 from both sides
3x = 4x + 8 |subtract 4x from both sides
-x = 8 |change the signs
<h3>x = -8</h3>
Answer:
The value of x = 0.41
Step-by-step explanation:
∵ 
Let 
∴ 
∴ 6y² - 5y = 6
∴ 6y² - 5y - 6 = 0 ⇒ factorize
∴ (3y + 2)(2y - 3) = 0
∴ 3y + 2 = 0 ⇒ 3y = -2 ⇒ y = -2/3
∴ 2y - 3 = 0 ⇒ 2y = 3 ⇒ y = 3/2
∵ 
∴
⇒ refused
(
never gives -ve values)
∵
⇒ insert <em>ln</em> in both sides
∵
⇒ <em>ln</em>(e) <em>= 1</em>
∴
∴ x = ln(3/2) = 0.41