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MAVERICK [17]
3 years ago
8

What is 214729.08 rounded to nearest thousand

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0
Hello!!

214,729.08 rounded to nearest thousand is 215,000.

And, 214,729.08 rounded to nearest thousandths (3 decimals) is 214,729.080.

Good luck :)
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Pls answer asap 7 - 3 r = r - 4 ( 2 + r)​
Marianna [84]

Answer:

no real answer

Step-by-step explanation:

distribute the -4 and combine all of the like terms on the left side = r-8-4r, then -8-3r

then we have 7-3r=-8-3r

from here, we can already tell that there's no real answer. this is because the two -3r will cancel, leaving no variable.

since 7 doesn't equal -8, there is no answer.

if, for example, the value on both sides of the equal sign were the same after the variable was eliminated, then your answer would be all real numbers

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2 years ago
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andreyandreev [35.5K]

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2 years ago
Write 34.8% as a fraction in simplest form.
balandron [24]

Answer:

87/250

Hope this helps!!

5 0
2 years ago
If your navigator tells you your position is 0.7 nautical miles from the West Point light, how far is that in feet? And how far
Nataly_w [17]

Answer:

that would be 4253.28 feet

that would be 1296.4 m

Step-by-step explanation:

I think that's the answer and I hope it helps :)

8 0
3 years ago
You measure 20 turtles' weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 11.5
Naily [24]

Answer: the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

Step-by-step explanation:

Formula for margin of error : E=\dfrac{z^*\times (Population\ standard\ deviation)}{\sqrt{Sample\ size}}

, where z* = Critical z-value.

Given: population standard deviation = 11.5 ounces

Sample size = 20

Z value for 90% confidence level = 1.645

margin of error (E) = \dfrac{1.645\times11.5}{\sqrt{20}}

\approx4.23

Hence, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

3 0
3 years ago
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