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11111nata11111 [884]

3 years ago

15

Write the equation y=-1/2x+3 in standard form.

1 answer:

cricket20 [7]3 years ago

7 0

Begin by multiplying both sides by 2 to get rid of the fraction. The standard form for a line is Ax + By = C, no fractions allowed. By multiplying we get 2y=-1x+3. Now move the -1x over by adding and we have the standard form we are looking for: x + 2y = 3.

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What is the value of x ?enter your answer as a decimal in the box

maksim [4K]

Answer:

$x=67.5\ ft$

Step-by-step explanation:

we know that

Triangles MNP and MAB are similar by AAA theorem

If two figures are similar, then the ratio of its corresponding sides is equal

so

$\frac{MB}{MP}=\frac{MA}{MN}$

substitute the values

$\frac{x}{97.5}=\frac{71.5-22}{71.5}$

$\frac{x}{97.5}=\frac{49.5}{71.5}$

$x=97.5*\frac{49.5}{71.5}=67.5\ ft$

4 0

4 years ago

A recipe for soup calls for 4 tablespoons of lemon juice and 1/2 cup of olive oil. The given recipe serves 2 people, but a cook

zlopas [31]

It’s B since Olive Oil needs to be in the batch for the Cooking batch.

5 0

3 years ago

Choose the correct simplification of the expression (a^3/b^7)2

pickupchik [31]

Answer:

(a/b)^3 times 2/(b^4)

or

2(a/b)^3times 1/(b^4)

or instead of 1/b^4 ------>b^-4

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The probability of drawing a red candy at random from a bag of 25 candies is 2/5. After 5 candies are removed from tehe bag, wha

yaroslaw [1]

Given:

The probability of drawing a red candy at random from a bag of 25 candies is $\dfrac{2}{5}$ .

To find:

The probability of randomly drawing a red candy from the bag after removing 5 candies from the bag.

Solution:

Let n be the number of red candies in the bag. Then, the probability of getting a red candy is:

$P(Red)=\dfrac{\text{Number of red candies}}{\text{Total candies}}$

$\dfrac{2}{5}=\dfrac{n}{25}$

$\dfrac{2}{5}\times 25=n$

$10=n$

After removing the 5 candies from the bag, the number of remaining candies is $25-5=20$ and the number of remaining red candies is $10-5=5$ .

Now, the probability of randomly drawing a red candy from the bag is:

$P(Red)=\dfrac{5}{20}$

$P(Red)=\dfrac{1}{4}$

Therefore, the required probability is $\dfrac{1}{4}$ .

3 0

3 years ago

Estimate the solution.<br> 549.58 divide by 4

dybincka [34]

549.58 divide by 4 would be 137.395

4 0

4 years ago