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3 years ago

Please help please please

Mathematics

1 answer:

Murrr4er [49]3 years ago

4 0

2 pages per hour.

the fractions can be turned to decimals easily, 4/5 is 0.8 and 2/5 is 0.4 . divide those decimals together and you get 2.

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Estimated probability of guessing correctly on more than 3 out of 5 true-false questions

Alik [6]

The probability of guessing 4 right is
.. (5C4)*(1/2)^5 = 5/32
The probability of guessing 5 right is
.. (5C5)*(1/2)^5 = 1/32

So, the probability of guessing 4 or 5 right is
.. (5+1)/32 = 6/32 = 0.1875

7 0

3 years ago

What Is the line of reflection between pentagons PQRST and P'Q'R'S'T' ?

Sergeu [11.5K]

Answer:

Step-by-step explanation:

From the diagram:

P(-4,6)→P'(4,6);
Q(-7,4)→Q'(7,4);
R(-6,1)→R'(6,1);
S(-2,1)→S'(2,1);
T(-1,4)→T'(1,4).

The general rule of this reflection is

(x,y)→(-x,y)

and this is reflection across the y-axis. The y-axis has the equation x=0.

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3 years ago

The other one is for the two variable equation y = 3x + 4 find the matching y value when x = 0

pav-90 [236]

In finding the matching value of one unknown variable when other is known we have to use substitution. By way of substitution, y = 3 (0) + 4; y = 4. Moreover, when the variable of the known variable is zero, we just have to identify the intercept of line in the equation. The number with no variable in its side is always the intercept of the equation.

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4 years ago

Which direction do positive angles "track" from the positive x-axis? _____

Alex73 [517]

The go counterclockwise to the right

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3 years ago

A survey was conducted to find out how many people use public transportation to get to work. The results for 4625 respondents ar

gregori [183]

Answer:

The standard error for the difference in proportions of males and females who use public transportation every working day is 0.015.

The conditions are met.

Step-by-step explanation:

The sample 1 (males), of size n1=2570 has a proportion of p1=0.389.

$p_1=X_1/n_1=1000/2570=0.389$

The sample 2 (females), of size n2=2055 has a proportion of p2=0.745.

$p_2=X_2/n_2=1532/2055=0.745$

The difference between proportions is (p1-p2)=-0.356.

$p_d=p_1-p_2=0.389-0.745=-0.356$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{1000+1532}{2570+2055}=\dfrac{2532}{4625}=0.547$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.547*0.453}{2570}+\dfrac{0.547*0.453}{2055}}\\\\\\s_{p1-p2}=\sqrt{0.000096+0.000121}=\sqrt{0.000217}=0.015$

Conditions for a normal distribution approximation:

The expected number of "failures" or "successes", whichever is smaller, has to be larger than 10.

For the males sample, we have p=0.389 and (1-p)=0.611. The sample size is n=2570, so we take the smallest proportion and chek the condition:

$n\cdot p=2570\cdot 0.389=999>10$

For the females sample, we have p=0.745 and (1-p)=0.255. The sample size is n=2055, so we take the smallest proportion and chek the condition:

$n\cdot (1-p)=2055\cdot 0.255=524>10$

The conditions are met.

6 0

3 years ago