X = 2/3 + 5/6 + 4/6 + 5/6 = 9/6 = 3/2
Answer:
D. $53,650
Hope this helps, sorry if it's wrong :)
Use Commutative Property: a + b = b + a
and Associative Property: (a + b) + c = a + (b + c)
34 + 0 + 18 +26 = (34 + 26) + 18 = 60 + 18 = 78
Answer:
0.9009
Step-by-step explanation:
Let X be the event that Current will flow
Let Y be the event that the first relay which is 1 is closed
Thus, we can say that every element of Y is in X, but X possesses more elements. Thus, Y ⊂ X.
Thus, we can say that;
P(X ∩ Y) = P(Y)
Thus, given that current flowed, the probability that relay 1 functioned will be expressed as;
P(Y | X) = (P(Y ∩ X))/P(X)
From earlier, we saw that P(X ∩ Y) = P(Y). Thus;
P(Y | X) = P(Y)/P(X)
From the question, P(Y) = 0.9
Since there are 3 relays, then we have;
P(X) = 1 - 0.1³ = 0.999
Thus;
P(Y | X) = 0.9/0.999
P(Y | X) = 0.9009
Percent means parts out of 100
80%=80/100=8/10=4/5
