Answer:
0.00558659217
Step-by-step explanation:
Y=x+1
3x+y=21
-----------
-x+y=1
3x+y=21
First do this. Change one (or both) of the equations so that the x and y are on one side, and the number is on the other. Make sure either the x or the y is the same in both equations (in this case, y) and then take one away from the other. The y will cancel out so you can work out x.
3x+y=21 -
-x+y=1
-----------
4x = 20
x = 5
Then add the x into one of the two equations to find out y.
3x + y = 21
(3*5) + y = 21
15 + y = 21
y = 6
To check, put both x any y into the other equation.
-5 + 6 = 1
If the answer is correct, you have correctly solved the equations.
x = 5
y = 6
:D
Answer:
The volume each of the four barrels of the same size will be at least 47.5 liters.
Step-by-step explanation:
Let the volume of each of the four barrels is v liters.
Now, the amount of water that can be held in the fifth barrel is 10 liters. The total capacity of holding water for the 5 barrels combines is at least 200 liters.
So, from the above-given information, we can write the inequality to determine the volume of each of the four barrels will be
10 + 4v ≥ 200
Solving this we get,
4v ≥ 190
⇒ v ≥ 47.5
Therefore, the volume each of the four barrels of the same size will be at least 47.5 liters. (Answer)
Answer:
![2\sqrt{5}](https://tex.z-dn.net/?f=%202%5Csqrt%7B5%7D%20)
Step-by-step explanation:
Use the distance formula.
Subtract the x-coordinates and square the difference.
3 - 7 = -4; (-4)^2 = 16
Subtract the y-coordinates and square the difference.
4 - 2 = 2; 2^2 = 4
Add the differences and take the square root of the sum.
16 + 4 = 20; sqrt(20) = sqrt(4 * 5) = 2sqrt(5)
distance = 2sqrt(5)
You can use the distance formula which does the same thing.
![d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=%20d%20%3D%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D%20)
![d = \sqrt{(7 - 3)^2 + (2 - 4)^2}](https://tex.z-dn.net/?f=%20d%20%3D%20%5Csqrt%7B%287%20-%203%29%5E2%20%2B%20%282%20-%204%29%5E2%7D%20)
![d = \sqrt{(4)^2 + (-2)^2}](https://tex.z-dn.net/?f=%20d%20%3D%20%5Csqrt%7B%284%29%5E2%20%2B%20%28-2%29%5E2%7D%20)
![d = \sqrt{16 + 4}](https://tex.z-dn.net/?f=%20d%20%3D%20%5Csqrt%7B16%20%2B%204%7D%20)
![d = \sqrt{20}](https://tex.z-dn.net/?f=%20d%20%3D%20%5Csqrt%7B20%7D%20)
![d = \sqrt{4 \times 5}](https://tex.z-dn.net/?f=%20d%20%3D%20%5Csqrt%7B4%20%5Ctimes%205%7D%20)
![d = \sqrt{4} \times \sqrt{5}](https://tex.z-dn.net/?f=%20d%20%3D%20%5Csqrt%7B4%7D%20%5Ctimes%20%5Csqrt%7B5%7D%20)
![d = 2\sqrt{5}](https://tex.z-dn.net/?f=%20d%20%3D%202%5Csqrt%7B5%7D%20)