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3 years ago

Plzzzz help will give brainliest to right answer!! Picture down below

Mathematics

1 answer:

Lynna [10]3 years ago

6 0

Answer:

The area of Triangle K is 160

Step-by-step explanation:

First, the question explains how Triangle K was a scale factor of 4, with Triangle J being the original. To find the dimensions of Triangle K, you multiply Triangle J's measurements by 4:

4 x 4 = 16

5 x 4 = 20

Now we know the dimensions of Triangle K, it's time to find the area;

Formula for finding area of a triangle: (H x B) / 2

16 (Height) multiplied by 20 (Base) is 320.

Now, we divide 320 by 2 to find our answer:

320 divided by 2 is 160.

160 will be your answer.

<h2>I hope this helped!</h2>

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Answer These Questions and show your work to be brainliest

Andre45 [30]

1. 20 of 40 is 50% 20/40 = 1/2 1/2 = 50%

2. It is 20% because 600 is 20% of 3000

3. 40% of 30 = 12 50 = 15 10% = 3 (get it)

4, 40% of 65 = 26 50%= 32.5 (get it)

3 0

4 years ago

What is -7/ 12 plus 7/10 in simplest form

VMariaS [17]

It would be: -7/12 + 7/10 = -35+42 /60 = 7/60

So, your final answer is 7/60

Hope this helps!

6 0

4 years ago

Read 2 more answers

What is: <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B4x%5E%7B2%7D%20-20x%2B25%20" id="TexFormula1" title=" \sqrt{4x^{2} -

Firdavs [7]

We are given :

$\sqrt{4x^{2}-20x+25}$

Step 1: factor the part inside square root

The function given inside square root is of quadratic form.

So let us try to factorise it using AC method.

Here A*C = 4*25 = 100

so we have to find factors of 100 that add up to give -20.

the two factors are -10 and -10.

Rewriting the function :

$4x^{2} -20x+25$

= $4x^{2} -10x-10x+25$

= $2x(2x-5) - 5(2x-5)$

= $(2x-5)^{2}$

Step 2:

Now we take square root of the factorised form

$\sqrt{(2x-5)^2}$

= $2x-5$

Answer : (2x-5)

3 0

3 years ago

Please answer this correctly

jarptica [38.1K]

Answer:

18 roses

Step-by-step explanation:

In the given stem-leaf chart, 18 is the smallest number having 1 as "stem" and 8 as "leaf".

4 0

3 years ago

Topic: The Quadratic Formula

Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

$x= \frac{-b +- \sqrt{b^2-4ac} }{2a}$

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² = x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

$x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1$

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

$x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\$

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

$x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2$

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0

3 years ago