Answer:
Upper limit 150
Lower bond 136
Step-by-step explanation:
Hello!
The study variable is:
X: measurement of IQ of a statistic instructor.
This variable has a normal distribution:
X~N(μ; σ²)
And the population standard deviation is known σ= 16
You need to construct a confidence interval for the population mean, for this, since the variable has a normal distribution and the population variance is known, the statistic to use is the standard normal
Z= X[bar] - μ ~N(0;1)
σ/√n
The formula for the interval is:
X[bar] ± *
Where
X[bar] is the sample mean
is the value under the Z distribution for the corresponding confidence level.
S is the population standard deviation. (should be sigma but it doesn't recognize the symbol)
[143 ± 1.96 * ]
[135,988; 150. 012] ≅ [136; 150]
I hope it helps!
Answer:
Step-by-step explanation:
Here, we have to calculate
From combination we know that,
Here,
n = 7 and r = 4, so putting these,
Answer:
The mean is 36
Step-by-step explanation:
A.) A= (1/2)absinC
b.) sinA/a, sinB/b, sinC/c
sin100/42, sin25/b, sinC/c
use these two fractions.
sin100/42= sin25/b
cross multiply next
b×sin100= 42×sin25
then divide on both sides by sin100
b=18
c.)measurementofA+measurementofB+measurementofC=180
100+25+C=180
125+C=180
-125 -125
The measurement of angle C is 55 degrees.
d.)A=(1/2)42×18×sin55
= 21×18×sin55
A =309.6 units squared
The distance varies between 670.1 million kilometers at their closest and 1172.7 million kilometers at their farthest. Hope this helps!