Answer:
Each students provides 13 pounds of meal
Step-by-step explanation:
Total students in Ms. Lee class = 220
Total pounds of food collected = 2,860
how many meals did each student provide?
Meals provided by each student = Total pounds of food collected / total number of students
= 2,860 / 220
= 13 pounds
Each students provides 13 pounds of meal
Note: 1.2 pounds of food equals one meal
1.2 pounds : 1 meal = 13 pounds : x meals
1.2/1 = 13/x
1.2 * x = 1 * 13
1.2x = 13
x = 13 / 1.2
= 10.83 meals
Approximately 11 meals to the nearest number
Note:1 kilogram is 2.2 pounds
1 kg : 2.2 pounds = x kg : 13 pounds
1/2.2 = x / 13
1 * 13 = 2.2 * x
13 = 2.2x
x = 13/2.2
= 5.91 kilogram
Approximately x = 6 kilograms
Answer:
∠ EFG = 83°, ∠ GCE = 97°
Step-by-step explanation:
Since FE and FG are tangents to the circle then
∠ FGC and ∠ FEC are right angles
The sum of the angles in quadrilateral CEFG = 360°
Sum the 4 angles and equate to 360
3x + 11 + 90 + 5x - 23 + 90 = 360, that is
8x + 168 = 360 ( subtract 168 from both sides )
8x = 192 ( divide both sides by 8 )
x = 24
Thus
∠ EFG = 3x + 11 = 3(24) + 11 = 72 + 11 = 83°
∠ GCE = 5x - 23 = 5(24) - 23 = 120 - 23 = 97°
Convert 3/4 into decimal form = 0.75
0.75 x 7 = 5.25
Convert 5.25 into a fraction = 5 1/4
In conclusion, 7 trails were conducted.
Hope this helps!:D
*If you need me to do #5, DM me!
3. The area of a triangle can be given by (just plug and chug as always):

The area of the triangle is
6ft².
4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):


Now we just add them:

So, the area of that pentagon is
108m².
5. You are actually wrong on this one because the area of a triangle is:

So, just halve your answer and it will be correct.
6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:

Multiply by 4 to get total area:

So, the area of the given rhombus is
25cm².