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3 years ago

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The test scores of 15 students are listed below. find the lower quartile (q1). 42 45 50 57 60 63 66 70 73 78 85 87 90 94 95

1 answer:

miskamm [114]3 years ago

3 0

From the test scores given:
<span> 42 45 50 57 60 63 66 70 73 78 85 87 90 94 95
splitting the values into 3 sets:
</span><span> (42 45 50 57 60 )(63 66 70 73 78)( 85 87 90 94 95)
from the first set we select the median:
</span>42 45 50 57 60
the median is 50
thus the first quartile will be 50

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Step-by-step explanation:

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Using this information we can formula:

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first, let's find the distance from AP, using the distance formula.

$r = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2 + (z_1 - z_2)^2}$

$AP = \sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2}$

similarly, we can find the distance BP

$BP = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

since both distances are exactly the same we can equate them

$AP = BP$

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we can simplify it a bit squaring both sides, and getting rid of the subscripts.

$(3 - x)^2 + (4 - y)^2 + (-5 - z)^2 = (-2 - x)^2 + (1 - y)^2 + (4 - z)^2$

what we have done here is formulated an equation which consists of any point P that will have the same distance from (3,4,-5) and (-2,1,4).

To put it more concretely,

This is the equation of the the plane from that consists of all points (P) from which the distance from both (3,4,-5) and (-2,1,4) are equal.

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