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solong [7]
2 years ago
8

What will be the value of the 22nd coefficient of a binomial raised to the power 25​

Mathematics
1 answer:
Alona [7]2 years ago
4 0

Step-by-step answer:

We are looking at the coefficient of the 22nd term of (x+y)^25.

Following the sequence, first term is x^0y^25, second term is x^1y^24, third term is x^2y^23...and so on,  22nd term is x^21y^4.

The twenty-second term of (x+y)^25 is given by the binomial theorem as

( 25!/(21!4!) ) x^21*y^4

=25*24*23*22/4! x^21y^4

= 12650 x^21 y^4

The coefficient required is therefore 12650, for a binomial with unit valued coefficients.

For other binomials, substitute the values for x and y and expand accordingly.

Question would have been more clearly stated if the actual binomial was given, as commented above.

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The population of a city has decreased by 38% since it was last measured. If the current population is 27,900, what what the pre
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<u>Answer: </u>

The population of a city has decreased by 38% since it was last measured. If the current population is 27,900 .Previous population of city was 45000.

<u> Solution: </u>

Given that current population of city is 27900.  

Also, population of a city has decreased by 38% since it was last measured.

Let assume that population of city when it was last measured = x

Decreased of 38% means x-38% of x . we can write this as,

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Equating above expression to the given value of current population, we get

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x=45000

Hence previous population of city was 45000.

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