I am setting the week hourly rate to x, and the weekend to y. Here is how the equation is set up:
13x + 14y = $250.90
15x + 8y = $204.70
This is a system of equations, and we can solve it by multiplying the top equation by 4, and the bottom equation by -7. Now it equals:
52x + 56y = $1003.60
-105x - 56y = -$1432.90
Now we add these two equations together to get:
-53x = -$429.30 --> 53x = $429.30 --> (divide both sides by 53) x = 8.10. This is how much she makes per hour on a week day.
Now we can plug in our answer for x to find y. I am going to use the first equation, but you could use either.
$105.30 + 14y = $250.90. Subtract $105.30 from both sides --> 14y = $145.60 divide by 14 --> y = $10.40
Now we know that she makes $8.10 per hour on the week days, and $10.40 per hour on the weekends. Subtracting 8.1 from 10.4, we figure out that she makes $2.30 more per hour on the weekends than week days.
You subtract 16 from each side of the equation.
Then it will say exactly what number 'n' is.
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The equation is n + 16 = 9
On the left side, you subtract 16 from (n + 16) and you have 'n'.
On the right side, you subtract 16 from 9 and you have -7 .
Now the equation says n = -7
Answer:
Karin can fold 7, 14 and 21 paper cranes in 1, 2 and 3 hours respectively.
Step-by-step explanation:
Please kindly see the attached for explanation.
Answer:
5.5p + 5 ≤ 60
10 pounds
Step-by-step explanation:
a) The maximum total cost he can spend is $60.
5.5 * p + 2 * 2.5 ≤ 60
Simplify.
5.5p + 5 ≤ 60
b) Solve 5.5p + 5 ≤ 60
Subtract 5 from both sides
5.5p ≤ 55
Divide both sides by 5.5
p ≤ 10
So, the maximum he can buy is 10 pounds of food
Answer:
C. Quadrant I
Step-by-step explanation:
For a fact, that with radioactive substance it will decay and never stop halving itself. So the line of amount of radioactive substance always halves in a specific time. This type of graph are done in a positive unit grids, never on a negative because that would mean, the radioactive substance rather decaying, its absorbing. So the answer will be Quadrant I.
Visual likewise graph given below.
