Using the binomial distribution, it is found that there is a:
a) 0.9298 = 92.98% probability that at least 8 of them passed.
b) 0.0001 = 0.01% probability that fewer than 5 passed.
For each student, there are only two possible outcomes, either they passed, or they did not pass. The probability of a student passing is independent of any other student, hence, the binomial distribution is used to solve this question.
<h3>What is the binomial probability distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 90% of the students passed, hence
.
- The professor randomly selected 10 exams, hence
.
Item a:
The probability is:

In which:




Then:

0.9298 = 92.98% probability that at least 8 of them passed.
Item b:
The probability is:

Using the binomial formula, as in item a, to find each probability, then adding them, it is found that:

Hence:
0.0001 = 0.01% probability that fewer than 5 passed.
You can learn more about the the binomial distribution at brainly.com/question/24863377
Answer:
Roses= $8.4
Daises= $15.6
Step-by-step explanation:
Let represent the daises and let r represent d roses
r + d= 24....equation 1
0.25r + 0.90d= 16.40.......equation 2
r= 25-d
Substitute 25-d for r in equation 2
0.25(25-d) + 0.90d= 16.40
6.25-0.25d+0.90d= 16.40
6.25+0.65d= 16.40
0.65d= 16.40-6.25
0.65d= 10.15
d= 10.15/0.65
d = 15.6
Sub 15.6 for d in equation 1
r+d= 24
r+15.6= 24
r= 24-15.6
= 8.4
Price of daises is $15.6
Roses is $8.4
Answer:
2.1/////_____\\\\\\
Step-by-step explanation:
hope this helps
You need to provide a homie wit some more details lol