I'm not really good at math, but i would appreciate it if i can get some help with this math problem. 2y^3-4x^2-4-1+3x^2-3y^3-y^
1 answer:
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Answer:
Step-by-step explanation:
When you factor each equation, you result in two of the factors canceling out, resulting in .
[Top Equation]
The middle number is 3 and the last number is -28.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get 3
Multiply together to get -28
Can you think of the two numbers?
Try -4 and 7:
-4+7 = 3
-4*7 = -28
Fill in the blanks in
(x+_)(x+_)
with -4 and 7 to get...
(x-4)(x+7)
[Bottom Equation]
The middle number is -7 and the last number is 12.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get -7
Multiply together to get 12
Can you think of the two numbers?
Try -3 and -4:
-3+-4 = -7
-3*-4 = 12
Fill in the blanks in
(x+_)(x+_)
with -3 and -4 to get...
(x-3)(x-4)