The slope is -1/2. When it’s in the equation like that, the slope is always the number that has the letter X next to it.
-8, -48, -288
or
-8, -4/3, -2/9
I solved this using a scientific calculator and in radians mode since the given x's is between 0 to 2π. After substitution, the correct pairs
are:
cos(x)tan(x) – ½ = 0
→ π/6 and 5π/6
cos(π/6)tan(π/6) – ½ = 0
cos(5π/6)tan(5π/6) – ½ = 0
sec(x)cot(x) + 2 =
0 → 7π/6 and 11π/6
sec(7π/6)cot(7π/6) + 2 = 0
sec(11π/6)cot(11π/6) + 2 = 0
sin(x)cot(x) +
1/sqrt2 = 0 → 3π/4 and 5π/4
sin(3π/4)cot(3π/4) + 1/sqrt2 = 0
sin(5π/4)cot(5π/4) + 1/sqrt2 = 0
csc(x)tan(x) – 2 = 0 → π/3 and 5π/3
csc(π/3)tan(π/3) – 2 = 0
csc(5π/3)tan(5π/3) – 2 = 0
Answer:
If it is number 5. the answer is 13
Step-by-step explanation:
take the largest number and subtract the smallest number.
Answer:
Volume of cylinder = 
Step-by-step explanation:
Given : A cylinder fits inside a square prism.
To find : The volume of cylinder
Solution : Refer the attached graph.
Area of circle =
Area of square =
Side of square = diameter of circle= 
Diameter = 2r
∴ Area of square= 

Area of circle is
of area of square.
Volume is always = area × height
Volume of prism = Area of square × h = 
Volume of cylinder = Area of circle × h = 
Now, rate

⇒Volume of cylinder is
of Volume of prism.
Volume of Cylinder =
Volume of cylinder = 
Volume of cylinder = 