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photoshop1234 [79]
3 years ago
5

How do I write 10^4 as a product of the same factor

Mathematics
1 answer:
mars1129 [50]3 years ago
8 0
10x10x10x10, you have to multiply 10 by 10 four times, since it's 10 to the power of 4.

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The answer to the question

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An octagon can be used to form a pure tessellation. T or F
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I think it is F. Because im just guessing.

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3 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
3 years ago
Your round-trip drive to work is 4310 4 3 10 miles. How many miles do you drive to and from work in 3 3 days? CLEAR CHECK
luda_lava [24]

Answer:

if the round trip to work is 10 miles (i cant tell how many because it says 4310 4 3 10 miles lol) then you would travel 30 miles in 3 days

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3 years ago
Hi, Can I get help with this calculus homework? #31 a and b
Sloan [31]

Answer:

-5/9 and -1

Step-by-step explanation:

1. to differentiate the given function; 2. to substitute the coordinates of the point.

5 0
3 years ago
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