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tatiyna
3 years ago
8

Solve the system of equations9x - 4y = -7 7x - 12y = 39x?y?​

Mathematics
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

x = -3

y = -5

(-3, -5)

Step-by-step explanation:

We can solve this system of equations by elimination. This is when you either add OR subtract the equations (depending on the situation) to <u>eliminate one variable</u>, allowing you to solve for the other. To do this, we need one variable with the same coefficient in BOTH equations.

9x - 4y = -7         X3=>     27x - 12y = -21        (New equation is still equivalent)

7x - 12y = 39

Both equations have negative "12y" in them. If you subtract - 12y from - 12y, you get 0, eliminating the variable. <u>Subtract the two equations.</u>

.    27x - 12y = -21         Subtract each term in the equation.

<u>-      7x - 12y = 39</u>         Keep equal signs aligned

.       20x - 0 = -60        'y' eliminated. -12y - (-12y) = 0

.             20x = -60        Isolate 'x'

.       20x/20 = -60/20        Divide both sides by 20

.                  x = -3        Solved for 'x'

<u>Substitute 'x' for -3</u> in any equation.

9x - 4y = -7        

9(-3) - 4y = -7         Substitute. Simplify multiplication.

-27 - 4y = -7         Isolate 'y' now

-27 + 27 - 4y = -7  + 27        Add 27 on both sides

-4y = 20        Left side cancelled out 27, right side simplified by adding.

-4y/-4 = 20/-4        Divide both sides by -4

y = -5       Solved for 'y'

Therefore the solution is when 'x' is -3 (x = -3) and when 'y' = -5 (y = -5).

You can also write the solution as an ordered pair, like coordinates, which are written (x, y). The solution would be (-3, -5).

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