The ages of Olivia and her brother are 10 years and 11 years respectively
Let x₁, and x₂ be the ages of Olivia and her brother respectively.
Given that Olivia's brother is twice her age minus 9 years.
⇒ x₂ = 2x₁ - 9 → equation 1
Also given that Olivia's brother is as old as half the sum of the ages of Olivia and both of her 12-year-old twin brothers.
⇒ x₂ = 1/2 × (x₁ + 12) → equation 2
Using equation 1 in equation 2, we get
2x₁ - 9 = 1/2 × (x₁ + 12)
⇒ 4x₁ - 18 = x₁ + 12 (multiplying by 2 on both sides)
⇒ 4x₁ - x₁ = 12 + 18
⇒ 3x₁ = 30
⇒ x₁ = 10 (dividing by 3 on both sides)
Using the value of x₁, in equation 1,
⇒ x₂ = 2(10) - 9
⇒ x₂ = 20 - 9
⇒ x₂ = 11
Therefore the ages of Olivia and her brother are 10 years and 11 years respectively.
Learn more at:
brainly.com/question/28016937
brainly.com/question/28016937
#SPJ9
Combine like terms.
3x+(x-8)= 120
4x-8= 120
Add 8 to both sides.
4x= 128
Divide by 4 into both sides.
x= 32
I hope this helps!
~cupcake
Answer:
1/2
Step-by-step explanation:
Answer:
Solving Steps
Use the quadratic formula
Multiply / Remove the parentheses / Evaluate
Calculate
Separate the solutions
Simplify
Answer:
dont really know buy im thinking its A.
Step-by-step explanation:
hope this helps somewhat
