Answer:
m<CDE=66 degrees.
Step-by-step explanation:
(1) Extend the segment DC so it intersects with line BA. Call the intersection F.
(2) Consider triangle BCF. In here, we are given m<ABC=24 deg. Since m<BCD = 90 deg, we known that m<BCF = 90 deg. Knowing two angles in the triangle BCF lets us determine the rhird angle m<BFC = 180-90-24 = 66 deg.
(3) Because of the fact that AB || DE and the fact that line DF intersects AB and DE, the angles <BFC and <CDE are congruent. Therefore m<CDE=66 deg.
Answer:
Hope help
Pls mark brainliest if it is a right answer
Because
and
are inversely proportional, there is some constant
such that
Given that
and
, we have
So when
, you have
The equation has the same solution as w / 3.9 = 3 is w+0.6=1.9
Given:
w / 3.9 = 3
cross multiply
w × 3 = 3.9
3w = 3.9
divide both sides by 3
w = 3.9 / 3
w = 1.3
<em>Check all that applies</em>
A. w+0.6=1.9
w = 1.9 - 0.6
w = 1.3
B. w-0.6 = 11.1
w = 11.1 + 0.6
w = 11.7
C. w+1.03=2.93
w = 2.93 - 1.03
w = 1.9
D. w-1.03=8.24
w = 8.24 + 1.03
w = 9.27
Therefore, the equation has the same solution as w / 3.9 = 3 is w+0.6=1.9
Learn more about equation:
brainly.com/question/2972832
Answer:
16π
Step-by-step explanation:
Given that:
The sphere of the radius = 
The partial derivatives of 
Similarly;
∴
Now; the region R = x² + y² = 12
Let;
x = rcosθ = x; x varies from 0 to 2π
y = rsinθ = y; y varies from 0 to 
dA = rdrdθ
∴
The surface area 
![= 2 \pi \times 4 \Bigg [ \dfrac{\sqrt{16-r^2}}{\dfrac{1}{2}(-2)} \Bigg]^{\sqrt{12}}_{0}](https://tex.z-dn.net/?f=%3D%202%20%5Cpi%20%5Ctimes%204%20%5CBigg%20%5B%20%5Cdfrac%7B%5Csqrt%7B16-r%5E2%7D%7D%7B%5Cdfrac%7B1%7D%7B2%7D%28-2%29%7D%20%5CBigg%5D%5E%7B%5Csqrt%7B12%7D%7D_%7B0%7D)
= 8π ( -2 + 4)
= 8π(2)
= 16π
