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VARVARA [1.3K]
3 years ago
10

Factor the expression 20x^2+22x-12

Mathematics
1 answer:
hjlf3 years ago
6 0

Answer:

2(5x-2) (2x+3)

Step-by-step explanation: You could take a two out of the equation and then factor.

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Wren is at the grocery store buying fruit. She buys x pounds of apples for $1.68 per pound. She buys 2 fewer pounds of grapes fo
Soloha48 [4]

Answer:

The number of pounds of apples is 4.5 and the number of pounds of grapes is 2.5

Step-by-step explanation:

Let

x ------> the number of pounds of apples

(x-2) -----> the number of pounds of grapes

we know that

Solve for x

 

so

therefore

The number of pounds of apples is 4.5 and the number of pounds of grapes is 2.5

4 0
3 years ago
Read 2 more answers
If the length of a rectangular garden is 2 feet less than the length of a house and the width of the garden is 5 feet less than
Goshia [24]

Answer:

A(h)  =  h²/2 - 6*h + 10

Step-by-step explanation:

The garden is rectangular, and area of a rectangle is:

A(r) = L*w

Where L is the length and w is the width of the rectangle

Now if we call "h" the length of the house, we have the following expressions

L = h - 2  and

w = h/2 - 5

The expression for the area f the ectangle as a function of the length of the house is:

A(h)  =  ( h - 2 )* ( h/2 -5 )

A(h)  = h²/2 - 5*h - h + 10

A(h)  =  h²/2 - 6*h + 10

3 0
3 years ago
What is the vertex form of the equation y=x^2+12x-9
luda_lava [24]
Find the vertex form
y = (x + 6)^2 - 45
8 0
4 years ago
Read 2 more answers
Answer
denis-greek [22]

Answer:

x = 1, y = 3

Step-by-step explanation:

Use the y and substitute it into the 2nd equation. Solve for x. Then use that answer to solve for y.

5 0
4 years ago
Which of the following is equal to the rational expression when x does not equal 3 or 1 x^2-9/(x-1)(x-3)
yuradex [85]

Answer:

b.  \frac{x+3}{x-1}

Step-by-step explanation:

Given expression is:

\frac{x^{2}-9 }{(x-1)(x-3)}

Let us factorize the numerator using the formula:

a^{2} -b^{2} =(a+b)(a-b)

\frac{(x+3)(x-3)}{(x-1)(x-3)}

Since x ≠ 3, let us cancel the common factor x - 3 in the numerator and in the denominator.

So, \frac{x^{2}-9 }{(x-1)(x-3)} =\frac{x+3}{x-1}

7 0
4 years ago
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