if its diameter is 12, then its radius is half that or 6.
![\textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=6 \end{cases}\implies V=\cfrac{4\pi (6)^3}{3}\implies V=\cfrac{4}{3}\cdot \pi \cdot 6^3 \\\\\\ V=\cfrac{864}{3}\cdot \pi \implies V=\cfrac{864}{3}\cdot 3.14\implies V\approx 904.32~cm^3](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20sphere%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D6%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B4%5Cpi%20%286%29%5E3%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B4%7D%7B3%7D%5Ccdot%20%5Cpi%20%5Ccdot%206%5E3%20%5C%5C%5C%5C%5C%5C%20V%3D%5Ccfrac%7B864%7D%7B3%7D%5Ccdot%20%5Cpi%20%5Cimplies%20V%3D%5Ccfrac%7B864%7D%7B3%7D%5Ccdot%203.14%5Cimplies%20V%5Capprox%20904.32~cm%5E3)
Your answer to this question would be 60 percent hope this helps
Answer:
Step-by-step explanation:
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5
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12
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48
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The sum is 20 okay by the way it’s wrong u
Answer:
<h2><u><em>
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Step-by-step explanation:
● A standard deck of cards has:
● 52 Cards in 13 values and 4 suits
● Suits are Spades, Clubs, Diamonds
and Hearts
● Each suit has 13 card values:
2-10, 3 “face cards” Jack, Queen, King (J, Q, K)
and and Ace (A)
Basic Card Probabilities
● If you draw a card at random, what is the
probability you get:
● A Spade? P(Spade)=13/52
● A Face card? P(Face Card)=12/52 (or simply 3/13)
● A Red Ace? P(Red Ace) = 2/52
