All categories

3 years ago

I’ll give brainliest if you answer quick!!!

Mathematics

2 answers:

Gekata [30.6K]3 years ago

7 0

Answer:

The answer is B:4

Step-by-step explanation:

Katarina [22]3 years ago

3 0

Area is square units, so the new area would be the scale factor squared:

Scale factor is 2, so the area would increase by 2^2 = 4

The answer is B.4

You might be interested in

Please help! picture attached :)

Radda [10]

Answer:

y=-3x+4

Step-by-step explanation:

im assuming that you need the equation of the table

to find slope, y2-y1/x2-x1 10-4/-2-0

6/-2=-3 slope=-3

y=mx+b just sub in the numbers from a point in the table

10=-3(-2)+b

10=6+b

b=4

y=-3x+b

4 0

2 years ago

Calvin had 30 minutes in time-out. For the first 23 1/3 minutes, Calvin counted spots on the ceiling. For the rest of the time,

scoundrel [369]

Answer: $\frac{20}{3}\ minutes$ or $6 \frac{2}{3}\ minutes$

Step-by-step explanation:

For this exercise you can convert the mixed number to an improper fraction:

1. Multiply the whole number part by the denominator of the fraction.

2. Add the product obtained and the numerator of the fraction (This will be the new numerator).

3. The denominator does not change.

Then:

$23\frac{1}{3}= \frac{(23*3)+1}{3}= \frac{70}{3}\ minutes$

You know that he had 30 minutes in time-out, he counted spots on the ceiling for $\frac{70}{3}$ minutes and the rest of the time he made faces at his stuffed tiger.

Then, in order to calculate the time Calvin spent making faces at his stuffed tiger, you need to subract 30 minutes and $\frac{70}{3}$ minutes:

$30\ min-\frac{70}{3}=(\frac{3(30)-70}{3})=\frac{20}{3}\ minutes$ or $6 \frac{2}{3}\ minutes$

7 0

3 years ago

Read 2 more answers

Evaluate the line integral c y3 ds,<br> c.x = t3, y = t, 0 â‰¤ t â‰¤ 3

Temka [501]

$\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\int_{t=0}^{t=3}t^3\sqrt{1^2+(3t^2)^2}\,\mathrm dt=\int_0^3t^3\sqrt{1+9t^4}\,\mathrm dt$

Take $u=1+9t^4$ so that $\mathrm du=36t^3\,\mathrm dt$ . Then

$\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\frac1{36}\int_{u=1}^{u=730}\sqrt u\,\mathrm du=\frac{730^{3/2}-1}{54}$

7 0

3 years ago

The price of a burger went from $6.00 to $8.00. What is the percent of change? This is increase and decrease

Lubov Fominskaja [6]

The cost of the burger went up 2%/ and you can also subtract 6 from8 and get the answer. Thank you have a nice day

7 0

3 years ago

Evaluate 7C3. 35 210 21 105

nydimaria [60]

$\bf _nC_r=\cfrac{n!}{r!(n-r)!}\qquad \qquad \qquad \qquad \qquad _7C_3=\cfrac{7!}{3!(7-3)!} \\\\\\ \textit{use the }[!]\textit{ factorial button or the }[_nC_r]\textit{ button in your calculator}$

8 0

3 years ago