Which of the following inequalities have -8 in its solution set?

1 answer:

3 0

To determine when -8 is a solution, you will replace each variable with -8 and see which statements are true.

A. x + 4, -8 + 4 = -4, this is not in between 0 and 1
B. x - 3, -8 - 3 = -11, not between -5 and 2
C. 8x + 7, 8(-8) + 7 = -57 is not between -1 and 1
D. 3x, 3(-8) = -24 is equal to -24, so this one is true

A. 5x, 5(-6) = -30 is not less than -35 or greater than 35
B. 3x - 2, 3(-6) - 2 = -20 is not between -5 and 1
C. 3x + 5, 3(-6) + 5 = -13 is between -16 and 11
D. x - 5, -6 - 5 = -11 is not between -8 and 3

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$\bf \begin{array}{ccll} \stackrel{x}{hours}&\stackrel{y}{cost}\\ \cline{1-2} 2&70\\ 5&115 \end{array}~\hspace{10em}(\stackrel{x_1}{2}~,~\stackrel{y_1}{70})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{115}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{115-70}{5-2}\implies \cfrac{45}{3}\implies 15$

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