Please show me how you got the answer thanks.

Carlos cut StartFraction 5 Over 12 EndFraction of a yard of cloth into 5 pieces of equal length. What was the length of each pie

erastovalidia [21]

Answer:

Each piece of cloth is (1/12) of a yard long.

Step-by-step explanation:

Carlus cut 5/12 of a yard of cloth into 5 pieces of equal length.

To find the length of each piece of cloth, we need to find the quotient between the length of the piece of cloth, and the number of pieces in which we divide it.

This is:

length = $\frac{(5/12)yd}{5} = \frac{5yd}{12*5} = \frac{1yd}{12} \frac{5}{5} = \frac{1 }{12} yd$

This means that the length of each piece of cloth is (1/12) of a yard long.

5 0

2 years ago

Karin’s teacher asked her to find 20% of 10. what is 20% of 10?

zysi [14]

Answer:

2

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Find x to the nearest hundreths

7nadin3 [17]

I'd say the answer is C.

5 0

2 years ago

Read 2 more answers

The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,

strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=400$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=80$ represent the population standard deviation

n=15 represent the sample size

2) Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$400-2.58\frac{80}{\sqrt{15}}=346.708$

$400+2.58\frac{80}{\sqrt{15}}=453.292$

So on this case the 99% confidence interval would be given by (346.708;453.292)

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that $t_{\alpha/2}=2.98$