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Katyanochek1 [597]
4 years ago
10

While shopping online, Ji Hun find a square rug with an area of

Mathematics
1 answer:
coldgirl [10]4 years ago
7 0
The answer is t in your brain
You might be interested in
Find the 37th term of 352,345,338
Mariulka [41]

Answer:

a_{37}=100

Step-by-step explanation:

Given that,

A sequence 352,345,338.

First term = 352

Common difference = 345-352 = -7

We need to find the 37th term of the sequence.

The nth term of an AP is given by :

a_n=a+(n-1)d\\\\a_{37}=352+36\times (-7)\\\\a_{37}=100

So, the 37th term of the sequence is 100.

8 0
3 years ago
The students at a High School earned money for an international animal rescue foundation. 82 seniors earned an average $26.75 pe
Anon25 [30]

Answer: A. $16.13

Step-by-step explanation:

Total students = 82+74+96+99 =351

Sum of earnings of 82 seniors  = $26.75  x 82= $2193.5

Sum of earnings of 74 juniors  = $12.25 x 74 = $906.5

Sum of earnings of 96 sophomores  = $15.50  x 96 = $1488

Sum of earnings of 99 freshmen  =  $10.85 x 99 = $1074.15

Total earnings =  $2193.5  + $906.5+  $1488 +$1074.15

= $5662.15

(Total earnings) ÷ (Total students )

= $5662.15÷ 351

= $16.13

4 0
3 years ago
Which of these numbers 3,4,18,111,123,340,345,456,555 are multiples of 33 but not 9?
LUCKY_DIMON [66]

Answer:

4 and 132

Step-by-step explanation:

4 x 33 = 132

the numbers 4 and 132 have nothing to do with 9, no matter what way you look at them

i hope this helps :)

4 0
3 years ago
A teacher had 18 red pens if the ratio of red pens to blue pens she owned was 3:5 how many pens did she have in total
babymother [125]

Answer:

48 pens in total.

3 0
3 years ago
Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Viefleur [7K]

Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

n = 1537, \pi = \frac{353}{1537} = 0.2297

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 - 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2087

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

7 0
3 years ago
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