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iogann1982 [59]
3 years ago
6

Which plane figure generates a cylinder when it rotates about the dash line?

Mathematics
1 answer:
monitta3 years ago
7 0
The first choice if you're using Plato !!
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Can anyone help me please?
Nadya [2.5K]

Answer:

s ≤ -18

Step-by-step explanation:

Multiply both sides of the inequality by -3. Since the multiplier is negative, you need to reverse the comparison symbol.

(-3)(-s/3) ≤ (-3)(6)

s ≤ -18

_____

If you multiply by a positive number, you don't need to reverse the symbol. Hence multiplying by 3 gives ...

-s ≥ 18

You can now add s to both sides:

0 ≥ 18 + s

and subtract 18 from both sides:

-18 ≥ s

Of course, this is the same relationship as ...

s ≤ -18

6 0
3 years ago
1 question for math............
Murrr4er [49]

Answer:

answer would be the first choice.

Step-by-step explanation:

you would need to factor out x from the expression, then factor out -3 from the expression, factor the expression using a^2-B^2=(a-b)(a+b), afterwards you factor out the 4 from the expression, and then the 3x. Next you would factor out 2x+1, reduce the expression with x-5, reduce the numbers with the greatest common divisor 2, you then reduce the expression with x-3, multiply the fractions, distribute 2 through the parenthesis, distribute the 3x through the parenthesis, and that should be all.

7 0
3 years ago
Read 2 more answers
Solve the equation for the given variable. justify each step.
s344n2d4d5 [400]

Answer: y=\frac{5-9x}{2}

s=-30+10t

Step-by-step explanation:

9x + 2y = 5; y

9x-9x+2y = 5-9x

2y=5-9x

y=\frac{5-9x}{2}

1/15s - 2/3t = -2; s

(1/15s - 2/3t = -2)*15     ==> Get rid of fraction by multiplying both sides by 15

s - 30/3 t=-30

s-10t=-30

s=-30+10t

5 0
1 year ago
Graph the function y = x+2+5. Which point lies on the graph?
sp2606 [1]

Answer:

<u>A</u>

Step-by-step explanation:

<u>Given equation</u> :

  • y = x + 2 + 5
  • y = x + 7

<u>Evaluating the options</u>

<u>A (-2, 5)</u>

  • 5 = -2 + 7
  • 5 = 5
  • Correct!
5 0
2 years ago
✓<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B19%20%2B%20%20%5Csqrt%7B30%20%2B%20%20%5Csqrt%7B32%20%2B%20x%20%20%7D%20%7D%
Setler79 [48]

We'll have to repeatedly square both sides of the equation, in order to get rid of the square roots. Squaring a first time yields

19+\sqrt{30+\sqrt{32+x}}=25

Move the 19 to the right hand side:

\sqrt{30+\sqrt{32+x}}=6

And square again:

30+\sqrt{32+x}=36 \iff \sqrt{32+x}=6

Square one last time:

32+x=36 \iff x=36-32=4

Let's check the solutions: all these squaring might have created external solutions:

\sqrt{19+\sqrt{30+\sqrt{32+4}}}=\sqrt{19+\sqrt{30+6}}=\sqrt{19+6}=\sqrt{25}=5

So, x=4 is a feasible solution.

8 0
3 years ago
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