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Airida [17]
4 years ago
9

Is y= 4x proportional?

Mathematics
2 answers:
tekilochka [14]4 years ago
6 0

Answer:

y is directly proportional to x

Step-by-step explanation:

Brilliant_brown [7]4 years ago
5 0
Yes

As long as there are no exponents or addition/subtraction it is proportional

I attached an image below that may help

Feel free to comment below to ask more questions :)
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Step-by-step explanation:

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3 years ago
Find the area of the circle. leave your answer in terms is pi.
PilotLPTM [1.2K]

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9

Step-by-step explanation:

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I don't get this pls help
dmitriy555 [2]

Answer:

  d, e

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

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In this case, it means the product is ...

  (6^1)(6^0)(6^-3) = 6^(1+0-3) = 6^-2 = 1/6^2 = 1/36

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The 6 without an exponent is equivalent to 6^1, an exponent of 1.

The sum of the exponents is -2.

Add the exponents to simplify the expression.

The value of the expression is 1/36.

An equivalent is any expression that results in 6^-2. One such is (6^5)(6^-7).

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Only the last two choices, d and e, apply.

3 0
4 years ago
Find the sum of the first one hundred positive integers. see fig 6.26
nignag [31]
Here's a pattern to consider:
1+100=101
2+99=101
3+98=101
4+97=101
5+96=101
.....
This question relates to the discovery of Gauss, a mathematician. He found out that if you split 100 from 1-50 and 51-100, you could add them from each end to get a sum of 101. As there are 50 sets of addition, then the total is 50×101=5050
So, the sum of the first 100 positive integers is 5050.

Quick note
We can use a formula to find out the sum of an arithmetic series:
s =  \frac{n(n + 1)}{2}
Where s is the sum of the series and n is the number of terms in the series. It works for the above problem.
8 0
3 years ago
Find an equation for a tangent plane z=e-x2-y2 at the point (0,0,1).
Nadya [2.5K]

Answer: equation of the tangent plane is z = 1

Step-by-step explanation:

Given equation

z = e^(-x²-y²) at point (0,0,1)

now let z = f(x,y)

Δf(x,y) = [ fx, fy ]

= (-2xe^(-x²-y²)), (-2ye^(-x²-y²))

now

Δf (0,0) = [ 0, 0 ] = [ a, b ]

equation of the tangent plane therefore will be

z - z₀ = a(x-x₀) + b(y-y₀)

z - 1 = 0(x-0) + 0(y-0)

z - 1 = 0 + 0

z = 1

Therefore equation of the tangent plane is z = 1

7 0
3 years ago
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