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lions [1.4K]
2 years ago
6

The expression 8x2 − 144x 864 is used to approximate a small town's population in thousands from 1998 to 2018, where x represent

s the number of years since 1998. choose the equivalent expression that is most useful for finding the year where the population was at a minimum. 8(x2 − 18x 108) 8(x2 − 18x) 108 8(x − 9)2 − 216 8(x − 9)2 216
Mathematics
1 answer:
Rzqust [24]2 years ago
8 0

The expression that is most useful for finding the year where the population was at a minimum would be 8(x − 9)² + 216.

Given expression 8x² − 144x + 864 is used to approximate a small town's population in thousands from 1998 to 2018, where x represents the number of years since 1998.

<h3>What is a quadratic equation?</h3>

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

Given expression is 8x² − 144x + 864

Let y = 8x² − 144x + 864

also,  y - 864 = 8x² - 144x

by Extracting common factor 8 on the right side

y - 864 = 8(x² - 18x)

Add (18/2)² on both sides, we get

y - 864 + 8(18/2)² = 8 (x² - 18x + 81²)

y - 864 + 648 = 8 (x² - 8x + 9)

on simplification

y - 216 = 8 (x - 9)²

y = 8(x - 9)² + 216

therefore, y = 8 (x - 9)² + 216

The expression that is most useful for finding the year where the population was at a minimum would be 8(x − 9)² + 216.

Learn more about a quadratic equation here:

brainly.com/question/2263981

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HI i neeed helppppppppppppppppp
elena-14-01-66 [18.8K]

Answer:

5

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A figure has vertices at L(3,3), M(2,4), and N(−1,0). After a transformation, the image of the figure has vertices at L′(2,−5),
alexandr402 [8]

The transformation was a reflection over the line x = -0.5

And the image and preimage can be seen in the graph below.

<h3>How to identify the preimage and image?</h3>

First, the original vertices are:

L(3, 3)

M(2, 4)

N(-1, 0)

3 vertices means that our figure is a triangle.

Now, the transformed vertices are:

L'(2, -5)

M'(3, -4)

N'(-1, 1)

And the graph of both sets can be seen below.

Now we can try to identify the transformation.

Now, notice that all the points (L, M, N, L', N', M') are equidistant to the horizontal line x = -0.5

This is a clear implication that the transformation was a reflection over the line x = -0.5

If you want to learn more about transformations:

brainly.com/question/4289712

#SPJ1

3 0
1 year ago
Round 392,153 to the nearest hundred thousand
Galina-37 [17]
392,000 would be the nearest <span>hundred thousand</span>
6 0
3 years ago
P(X&lt; ) 1-P(X&gt; ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 30, p = 0.626

So

\mu = E(X) = np = 30*0.626 = 18.78

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0
3 years ago
4=y-4 solve for the variable
sdas [7]
4 = y - 4
You need to add 4 on each side and you will get 8 which means that y is equal to 8.

4 = y - 4
+4 +4
8=y
6 0
3 years ago
Read 2 more answers
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